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What Is the Exact Value of Sin 15 Degrees

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How to Find Sin 15 Degrees Using Angle Difference Formula

The concept of Value of Sin 15 is a foundational trigonometric result that helps in solving trigonometry questions efficiently. It is highly relevant in board exams, entrance tests, and many real-life applications requiring angle calculations.


What Is Value of Sin 15?

The value of sin 15 refers to the exact trigonometric ratio for a 15° angle, where sine (sin) represents the ratio of the length of the side opposite the angle to the hypotenuse in a right triangle. This concept is directly applied in trigonometric calculations, geometry, and physics, and appears frequently in class 10, 11, and 12 Maths exams. You’ll find this concept applied in trigonometric values, compound angle formulas, and MCQ-based competitive exams.


Key Formula for Value of Sin 15

Here’s the standard formula:
\( \sin 15^\circ = \frac{\sqrt{6} - \sqrt{2}}{4} \approx 0.2588 \)


Why Is Value of Sin 15 Important?

The value of sin 15 is often not memorized like sin 0°, 30°, 45°, 60°, or 90°, but questions based on it are very common. Knowing how to calculate or recall sin 15 can help you answer trigonometric problems quickly and accurately in school board exams, JEE, NEET, SAT and even real-life situations where precise angle measurement is needed.


Step-by-Step Derivation Using Compound Angle Formula

Let’s prove sin 15° step by step using the compound angle (difference) formula:

  1. Write 15° as (45° − 30°).
  2. Apply the formula: \( \sin(A - B) = \sin A \cos B - \cos A \sin B \).
  3. Let A = 45°, B = 30°.
    \( \sin 15^\circ = \sin 45^\circ \cos 30^\circ - \cos 45^\circ \sin 30^\circ \)
  4. Substitute standard values:
    \( \sin 45^\circ = \frac{1}{\sqrt{2}} \), \( \cos 30^\circ = \frac{\sqrt{3}}{2} \),
    \( \cos 45^\circ = \frac{1}{\sqrt{2}} \), \( \sin 30^\circ = \frac{1}{2} \)
  5. Calculate:
    \( = \frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} \times \frac{1}{2} \)
    \( = \frac{\sqrt{3}}{2\sqrt{2}} - \frac{1}{2\sqrt{2}} \)
    \( = \frac{\sqrt{3} - 1}{2\sqrt{2}} \)
  6. Rationalise the denominator:
    Multiply the numerator and denominator by \( \sqrt{2} \):
    \( = \frac{(\sqrt{3} - 1) \times \sqrt{2}}{2\sqrt{2} \times \sqrt{2}} = \frac{\sqrt{6} - \sqrt{2}}{4} \)
  7. Decimal approximation:
    \( \sqrt{6} \approx 2.449 \), \( \sqrt{2} \approx 1.414 \), so
    \( \frac{2.449 - 1.414}{4} = \frac{1.035}{4} \approx 0.2588 \)

Sin 15 in Root, Fraction and Decimal Forms

Form Value Remarks
Root Form \( \frac{\sqrt{6} - \sqrt{2}}{4} \) Exact value, suits board exam proofs
Fraction (+rationalised root) \( \frac{(\sqrt{3} - 1)}{2\sqrt{2}} \) Also accepted in exams
Decimal 0.2588 Up to 4 decimal places

Visual Representation: Sin 15 on Unit Circle

On the unit circle, the value of sin 15° is the y-coordinate of the point corresponding to a 15° angle from the positive x-axis. Since 15° is in the first quadrant, sin 15° is positive. Its approximate value (0.2588) means that for a radius of 1, the height from the x-axis up to the curve at 15° is 0.2588 units.


Trigonometric Values Table (Quick Revision)

Angle (°) sin cos tan
0 0 1 0
15 \( \frac{\sqrt{6} - \sqrt{2}}{4} \) \( \frac{\sqrt{6} + \sqrt{2}}{4} \) 0.2679
30 \( \frac{1}{2} \) \( \frac{\sqrt{3}}{2} \) 0.5774
45 \( \frac{1}{\sqrt{2}} \) \( \frac{1}{\sqrt{2}} \) 1
60 \( \frac{\sqrt{3}}{2} \) \( \frac{1}{2} \) 1.732
90 1 0 undefined

Speed Trick or Vedic Shortcut

You don't have to memorize sin 15 as a new value—just break it into known angles (like 45° and 30°) and use the compound angle formula. If you forget that, just remember this pattern: “sin(small angle) = sin(known – known)”. Most students know sin 45 and sin 30, so combine them as shown above to save exam time.


Common Mistakes and Tips

  • Forgetting to rationalise the denominator.
  • Mixing the order of subtraction in the numerator.
  • Using decimal approximations instead of exact values in proofs.
  • Confusing sin 15° with sin 150° (which equals 1/2).
  • Not remembering which quadrant 15° belongs to (it's positive).

Relation to Other Values and Formulas

Value of cos 15 is \( \frac{\sqrt{6} + \sqrt{2}}{4} \); both are useful when solving length, height, or distance problems. Also note that:
sin 150° = sin(180° − 30°) = sin 30° = 1/2,
sin 15 is much less than sin 30,
sin 75° = cos 15°.
Mastering these values helps with many trigonometry applications and conversions between different angle measures.


Try These Yourself

  • Find the value of sin 75° in exact form.
  • Prove that cos 15° = (√6 + √2)/4.
  • If sin A = sin 15°, what is A in degrees (for 0 ≤ A < 180°)?
  • Simplify: 2 × sin 15° × cos 15°.

Wrapping It All Up

We explored the value of sin 15—from its definition to the proof, shortcut tips, mistakes, and how it connects to related formulas. With these methods, you’ll be able to answer trigonometry questions more confidently and accurately. Practice with Vedantu for more tips and detailed explanations that make exam prep easier!


Further Reading and Related Topics


FAQs on What Is the Exact Value of Sin 15 Degrees

1. What is the value of sin 15°?

The exact value of sin 15° is (√6 − √2) / 4. This value is obtained using the angle subtraction identity:

  • 15° = 45° − 30°
  • sin(A − B) = sin A cos B − cos A sin B
  • sin 15° = sin 45° cos 30° − cos 45° sin 30°
  • = (√2/2 × √3/2) − (√2/2 × 1/2)
  • = (√6 − √2) / 4
This is an exact trigonometric value commonly used in exams and competitive maths problems.

2. How do you find the exact value of sin 15° using identities?

You can find sin 15° by using the angle subtraction identity sin(A − B). Follow these steps:

  • Write 15° as 45° − 30°
  • Apply sin(A − B) = sin A cos B − cos A sin B
  • Substitute known values: sin 45° = √2/2, cos 30° = √3/2, cos 45° = √2/2, sin 30° = 1/2
  • Simplify to get (√6 − √2) / 4
This method gives the exact trigonometric value without using a calculator.

3. What is the decimal value of sin 15°?

The decimal value of sin 15° is approximately 0.2588. Using the exact form (√6 − √2)/4 and evaluating:

  • √6 ≈ 2.449
  • √2 ≈ 1.414
  • (2.449 − 1.414) / 4 ≈ 1.035 / 4 ≈ 0.2588
This approximation is useful for numerical calculations in trigonometry problems.

4. Is sin 15° a rational or irrational number?

The value of sin 15° is an irrational number. Since sin 15° = (√6 − √2)/4 and both √6 and √2 are irrational, their difference divided by 4 remains irrational. Therefore, sin 15° cannot be written as a simple fraction of integers.

5. How is sin 15° related to sin 45° and sin 30°?

The value of sin 15° is derived from sin 45° and sin 30° using the identity sin(A − B). Specifically:

  • 15° = 45° − 30°
  • sin 15° = sin 45° cos 30° − cos 45° sin 30°
By substituting known special angle values, we get (√6 − √2) / 4. This shows how special angles are interconnected in trigonometry.

6. What is the value of sin 15° in radians?

The value of sin 15° in radians is the same as sin(π/12), which equals (√6 − √2) / 4. Since 15° = π/12 radians, the sine value does not change—only the angle unit changes. Thus, sin(π/12) = sin 15°.

7. Can you derive sin 15° using the half-angle formula?

Yes, sin 15° can be derived using the half-angle identity since 15° is half of 30°. Using:

  • sin(θ/2) = √[(1 − cos θ)/2]
  • Let θ = 30°
  • sin 15° = √[(1 − cos 30°)/2]
  • = √[(1 − √3/2)/2]
Simplifying gives (√6 − √2) / 4, confirming the exact value.

8. What quadrant does 15° lie in and is sin 15° positive?

The angle 15° lies in the first quadrant, and therefore sin 15° is positive. In the first quadrant (0° to 90°), all trigonometric ratios—sin, cos, and tan—are positive. Hence, sin 15° = (√6 − √2)/4 is a positive value.

9. What is the difference between sin 15° and cos 15°?

The exact values are sin 15° = (√6 − √2) / 4 and cos 15° = (√6 + √2) / 4. Using angle identities:

  • sin 15° = sin(45° − 30°)
  • cos 15° = cos(45° − 30°)
The only difference is the sign between the square root terms—sin has subtraction, while cos has addition.

10. Where is the exact value of sin 15° used in mathematics?

The exact value sin 15° = (√6 − √2) / 4 is commonly used in trigonometric identities, calculus, coordinate geometry, and competitive exams. It helps in:

  • Simplifying trigonometric expressions
  • Solving triangles without a calculator
  • Proving identities
  • Evaluating integrals and limits involving special angles
Knowing exact trigonometric values improves accuracy in higher-level mathematics.