Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

Two water pipes of diameters 2cm and 4cm are connected with the main supply line. the velocity of flow of water in the pipe of $2cm$ diameter is:
A) $4$ times that in the other pipe
B) $\dfrac{1}{4}$ times that in the other pipe
C) $2$ times that in the other pipe
D) $\dfrac{1}{2}$ times that in the other pipe

seo-qna
Last updated date: 17th Sep 2024
Total views: 80.4k
Views today: 0.80k
SearchIcon
Answer
VerifiedVerified
80.4k+ views
Hint: Here, by using the velocity formula, we have to calculate the radius of the pipes and separate the diameter, then proceed to find the flow of water in a particular diameter and then the vector defines the solution and compares the diameter of the other pipe.

Formula used:
According to that velocity of pipes
${A_x}{v_x} = {A_y}{v_y}$
Where,
${v_x}$ and ${v_y}$ are the velocity of water in pipes\[X\]and $Y$respectively.
The radius of $X,\,{r_x} = \dfrac{{dx}}{2}$
The radius of $Y,{r_y} = \dfrac{{dy}}{2}$
$dx,dy$ is differentiation with respect to a particular variable.

Complete step by step solution:
Given by ,
The diameter of the vector pipes
Let, $X = 2cm$ and $Y = 4cm$ respectively
We know that ,
Radius formula
The radius of $X,\,{r_x} = \dfrac{{dx}}{2}$
The radius of $Y,{r_y} = \dfrac{{dy}}{2}$
The value of $dx = 2$ and \[dy = 4\]
Substituting the given value in above equation,
We get,
The radius of $X$ and \[Y\]
${r_x} = 0.01\,m$
${r_y} = 0.02\,m$
According to the equation of continuity:
$\Rightarrow {A_x}{v_x} = {A_y}{v_y}$
$\Rightarrow {A_x} = \pi \left( {{r_x}} \right)$ and ${A_y} = \pi \left( {{r_y}} \right)$
Substituting the given value in above equation,
we get,
$\Rightarrow \pi {\left( {0.01\,m} \right)^2} \times {v_x} = \pi {\left( {0.02\,m} \right)^2}{v_y}$
Rearranging the given equation,
We have,
$\Rightarrow {v_x} = \dfrac{{{{\left( {0.02\,m} \right)}^2}}}{{{{\left( {0.01\,m} \right)}^2}}}{v_y}$
On simplifying,
We get, ${v_x} = 4{v_y}$
Therefore the velocity of flow of water in the pipe of $2cm$ diameter $X$ in four times that of in pipe $Y$

Hence, option A is the correct answer.

Note: If we have to calculate the pipe radius and compare the diameter of the other pipe. A flow rate increase or decrease will result in a corresponding velocity increase or decrease. Velocity is also influenced by pipe size. Reducing pipe size increases the velocity, which increases friction, given a constant flow rate.