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**Hint:**By the given data, compare the acceleration of the block and the observer and the acceleration of the block and the second trolley. Use the formula of the force given below, substitute the known values, to find the value of the frictional force.

**Formula used:**

By the Newton’s second law of motion,

$F = ma$

Where $F$ is the force acting on the block, $m$ is the mass of the block and $a$ is the acceleration of the block.

**Complete step by step solution:**

It is given that the acceleration of the trolley one is ${a_1}$.The acceleration of the trolley two is ${a_2}$.The mass of the block on the trolley one is $m$.The frame of the observer is in equilibrium with the block.Let the acceleration of block of mass with respect to

the observer on trolley 2 be denoted as ${a_{bo}}$.

This shows that the acceleration of the block of mass and the observer are the same.

${a_{bo}} = 0$

${a_b} - {a_o} =0 $

where ${a_b}$ denotes the acceleration of the block with respect to ground and ${a_o}$ denotes the acceleration of the observer with respect to ground.

Since the observer stands on the trolley two, the acceleration of the observer and the trolley two are the same.

$\Rightarrow {a_b} = {a_2}$--(1)

Let us assume that only frictional force acts on the block. Using the formula of motion,

$\Rightarrow F = ma$

$\Rightarrow F = m{a_b}$

Substitute (1) in the above step, we get

$\Rightarrow F = m{a_2}$

**Hence the frictional force on the block is $m{a_2}$.**

**Note:**The frictional force is the force that acts between the two surfaces that keeps the object to remain in place without movement. It has many kinds of use in daily life. We are able to stand only due to friction between the ground and toes.

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