
Two trolleys 1 and 2 are moving with acceleration ${a_1}$ and ${a_2}$ respectively in the same direction. A block of mass “ $m$ “ on trolley $1$ is in equilibrium from the frame of observer stationary w.r.t trolley $2$. The magnitude of friction force on the block due to the trolley is (assume that no horizontal force other than frictional force is acting on the block).
Answer
217.8k+ views
Hint: By the given data, compare the acceleration of the block and the observer and the acceleration of the block and the second trolley. Use the formula of the force given below, substitute the known values, to find the value of the frictional force.
Formula used:
Complete step by step solution:
Note: The frictional force is the force that acts between the two surfaces that keeps the object to remain in place without movement. It has many kinds of use in daily life. We are able to stand only due to friction between the ground and toes.
Formula used:
By the Newton’s second law of motion,
$F = ma$
Where $F$ is the force acting on the block, $m$ is the mass of the block and $a$ is the acceleration of the block.
Complete step by step solution:
It is given that the acceleration of the trolley one is ${a_1}$.The acceleration of the trolley two is ${a_2}$.The mass of the block on the trolley one is $m$.The frame of the observer is in equilibrium with the block.Let the acceleration of block of mass with respect to
the observer on trolley 2 be denoted as ${a_{bo}}$.
This shows that the acceleration of the block of mass and the observer are the same.
${a_{bo}} = 0$
${a_b} - {a_o} =0 $
where ${a_b}$ denotes the acceleration of the block with respect to ground and ${a_o}$ denotes the acceleration of the observer with respect to ground.
Since the observer stands on the trolley two, the acceleration of the observer and the trolley two are the same.
$\Rightarrow {a_b} = {a_2}$--(1)
Let us assume that only frictional force acts on the block. Using the formula of motion,
$\Rightarrow F = ma$
$\Rightarrow F = m{a_b}$
Substitute (1) in the above step, we get
$\Rightarrow F = m{a_2}$
Hence the frictional force on the block is $m{a_2}$.
Recently Updated Pages
Arithmetic, Geometric & Harmonic Progressions Explained

Cartesian Form of Vector Explained: Formula, Examples & Uses

Apparent Frequency Explained: Formula, Uses & Examples

Calorimetry: Definition, Principles & Calculations

Centrifugal Force Explained: Definition, Formula & Examples

Charge in a Magnetic Field: Definition, Formula & Examples

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

