
$3$ mole of gas ''$X$" and 2 moles of gas "$Y$" enters from the end "$P$" and "$Q$" of the cylinder respectively. The cylinder has the area of cross section, shown as under
the length of the cylinder is $150cm$. The gas "$x$" intermixes with gas "$y$" at this point. If the molecular weight of the gases $x$ and $y$ is $20$ and $80$ respectively, then what will be the distance of point $A$ from $Q$?
(A) $75cm$
(B) $50cm$
(C) $37.5cm$
(D) $90cm$
Answer
125.7k+ views
Hint: Molecular weight is an amount of the sum of the atomic weight values of the atoms in a molecule. Molecular weight is used in chemistry to define stoichiometry in chemical reactions and equations. Molecular weight is normally abbreviated by $M.W$ or $MW$. Molecular weight is either unit less or expressed in terms of atomic mass units (amu) or Daltons ($Da$).
Formula Used:
$\dfrac{{rx}}{{ry}} = \dfrac{{{w_x}}}{{{n_y}}}\sqrt {\dfrac{{{M_y}}}{{{M_x}}}} $
Complete Step by step solution:
So we know the equation
$\dfrac{{rx}}{{ry}} = \dfrac{{{w_x}}}{{{n_y}}}\sqrt {\dfrac{{{M_y}}}{{{M_x}}}} $
Here, ${M_x}$ and ${M_y}$ represent the molecular weight of the gasses $X$ and $Y$.
Now substituting the values in the above equation
$\dfrac{{rx}}{{ry}} = \dfrac{3}{2}\sqrt {\dfrac{{80}}{{20}}} = \dfrac{3}{1} = 3:1$
So distance travelled by the gas $X$ is $3$ and distance travelled by the gas $Y$ is $1$.
Hence it can be written as
$\dfrac{{dis\tan ce{\text{ }}travelled{\text{ }}by{\text{ }}gas{\text{ }}X}}{{dis\tan ce{\text{ }}travelled{\text{ }}by{\text{ }}gas{\text{ }}Y}} = 3:1$
So now we can calculate the distance of $A$ from $Q$.
$\therefore $ Distance of $A$ from $Q = \dfrac{{150}}{3} = 50cm$
Hence option B is correct
Additional Information
The molecular weight of a molecule or polymer is related to its properties. As the molecular weight increases their mechanical properties also increase. Every molecule has ideal weight and the different properties are optimized. The number of average molecular weights is stated as the total weight of a molecule divided by the total number of molecules.
Note:
The mole is the unit of measurement for the amount of substance in the International System of Units. A mole of a substance or a mole of particles is well-defined as exactly particles, which may be atoms, molecules, ions, or electrons. In short, for particles, $1mol = 6.02214076 \times {10^{23}}.$ Remember to find distance travelled by particle or molecule we will divide the length by number of particles or molecules given.
Formula Used:
$\dfrac{{rx}}{{ry}} = \dfrac{{{w_x}}}{{{n_y}}}\sqrt {\dfrac{{{M_y}}}{{{M_x}}}} $
Complete Step by step solution:
So we know the equation
$\dfrac{{rx}}{{ry}} = \dfrac{{{w_x}}}{{{n_y}}}\sqrt {\dfrac{{{M_y}}}{{{M_x}}}} $
Here, ${M_x}$ and ${M_y}$ represent the molecular weight of the gasses $X$ and $Y$.
Now substituting the values in the above equation
$\dfrac{{rx}}{{ry}} = \dfrac{3}{2}\sqrt {\dfrac{{80}}{{20}}} = \dfrac{3}{1} = 3:1$
So distance travelled by the gas $X$ is $3$ and distance travelled by the gas $Y$ is $1$.
Hence it can be written as
$\dfrac{{dis\tan ce{\text{ }}travelled{\text{ }}by{\text{ }}gas{\text{ }}X}}{{dis\tan ce{\text{ }}travelled{\text{ }}by{\text{ }}gas{\text{ }}Y}} = 3:1$
So now we can calculate the distance of $A$ from $Q$.
$\therefore $ Distance of $A$ from $Q = \dfrac{{150}}{3} = 50cm$
Hence option B is correct
Additional Information
The molecular weight of a molecule or polymer is related to its properties. As the molecular weight increases their mechanical properties also increase. Every molecule has ideal weight and the different properties are optimized. The number of average molecular weights is stated as the total weight of a molecule divided by the total number of molecules.
Note:
The mole is the unit of measurement for the amount of substance in the International System of Units. A mole of a substance or a mole of particles is well-defined as exactly particles, which may be atoms, molecules, ions, or electrons. In short, for particles, $1mol = 6.02214076 \times {10^{23}}.$ Remember to find distance travelled by particle or molecule we will divide the length by number of particles or molecules given.
Recently Updated Pages
JEE Main 2023 (April 8th Shift 2) Physics Question Paper with Answer Key

JEE Main 2023 (January 30th Shift 2) Maths Question Paper with Answer Key

JEE Main 2022 (July 25th Shift 2) Physics Question Paper with Answer Key

Classification of Elements and Periodicity in Properties Chapter For JEE Main Chemistry

JEE Main 2023 (January 25th Shift 1) Maths Question Paper with Answer Key

JEE Main 2023 (January 24th Shift 2) Chemistry Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Login 2045: Step-by-Step Instructions and Details

Class 11 JEE Main Physics Mock Test 2025

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
