Two Plano convex lenses of focal lengths ${f_1}$ and ${f_2}$ set for minimising spherical aberration are kept apart by $2cm$. If the equivalent focal length of combination is $10cm$, the values of ${f_1}$ and ${f_2}$are :
(A) $18cm,16cm$
(B) $18cm,20cm$
(C) $20cm,22cm$
(D) $14cm,20cm$
Answer
261k+ views
Hint: In order to solve this question, we will first find the value of ${f_2}$ in terms of ${f_1}$ and then by using the general lens combination formula, we will solve for the value of both the focal length of two Plano-convex lenses.
Formula used:
If ${f_1}$ and ${f_2}$ are the focal length of two lenses and they are kept at a distance of d then their combined focal length is calculated using formula $\dfrac{1}{{{f_{net}}}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{{f_2}}} - \dfrac{d}{{{f_1}{f_2}}}$
Complete answer:
We have given that two Plano convex lenses has a focal length of ${f_1}$ and ${f_2}$,and they are kept at a distance of $d = 2cm$ so, for minimum spherical aberration we have
$
{f_2} - {f_1} = 2 \\
\Rightarrow {f_2} = 2 + {f_1} \\
$
Now, using the formula $\dfrac{1}{{{f_{net}}}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{{f_2}}} - \dfrac{d}{{{f_1}{f_2}}}$ where ${f_{net}} = 10cm$ is given to us and solving for ${f_1}$ we get,
$
\dfrac{1}{{10}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{(2 + {f_1})}} - \dfrac{2}{{{f_1}(2 + {f_1})}} \\
\dfrac{1}{{10}} = \dfrac{{2 + {f_1} + {f_1} - 2}}{{{f_1}(2 + {f_1})}} \\
\dfrac{1}{{10}} = \dfrac{2}{{(2 + {f_1})}} \\
$
Rearranging the above equation we get,
$
2 + {f_1} = 20 \\
\Rightarrow {f_1} = 18cm \\
$
and from the relation ${f_2} = 2 + {f_1}$ we get,
$
{f_2} = 18 + 2 \\
{f_2} = 20cm \\
$
So, The focal length of two Plano convex lenses are
$
{f_1} = 18cm \\
{f_2} = 20cm \\
$
Hence, the correct option is (B) $18cm,20cm$
Note: It should be remembered that in the case of minimum aberration the difference in the focal length of Plano-convex lenses is equal to the actual distance between them and the SI unit of focal length is meter whereas the inverse of focal length is known as Power whose SI unit is known as Dioptre.
Formula used:
If ${f_1}$ and ${f_2}$ are the focal length of two lenses and they are kept at a distance of d then their combined focal length is calculated using formula $\dfrac{1}{{{f_{net}}}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{{f_2}}} - \dfrac{d}{{{f_1}{f_2}}}$
Complete answer:
We have given that two Plano convex lenses has a focal length of ${f_1}$ and ${f_2}$,and they are kept at a distance of $d = 2cm$ so, for minimum spherical aberration we have
$
{f_2} - {f_1} = 2 \\
\Rightarrow {f_2} = 2 + {f_1} \\
$
Now, using the formula $\dfrac{1}{{{f_{net}}}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{{f_2}}} - \dfrac{d}{{{f_1}{f_2}}}$ where ${f_{net}} = 10cm$ is given to us and solving for ${f_1}$ we get,
$
\dfrac{1}{{10}} = \dfrac{1}{{{f_1}}} + \dfrac{1}{{(2 + {f_1})}} - \dfrac{2}{{{f_1}(2 + {f_1})}} \\
\dfrac{1}{{10}} = \dfrac{{2 + {f_1} + {f_1} - 2}}{{{f_1}(2 + {f_1})}} \\
\dfrac{1}{{10}} = \dfrac{2}{{(2 + {f_1})}} \\
$
Rearranging the above equation we get,
$
2 + {f_1} = 20 \\
\Rightarrow {f_1} = 18cm \\
$
and from the relation ${f_2} = 2 + {f_1}$ we get,
$
{f_2} = 18 + 2 \\
{f_2} = 20cm \\
$
So, The focal length of two Plano convex lenses are
$
{f_1} = 18cm \\
{f_2} = 20cm \\
$
Hence, the correct option is (B) $18cm,20cm$
Note: It should be remembered that in the case of minimum aberration the difference in the focal length of Plano-convex lenses is equal to the actual distance between them and the SI unit of focal length is meter whereas the inverse of focal length is known as Power whose SI unit is known as Dioptre.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

