Two parallel infinite line charges $ + \lambda $ and $ - \lambda $ are placed with a separation distance R in free space. The net electric field exactly midway between the two line charges is
(A) Zero
(B) $\dfrac{{2\lambda }}{{\pi {E_0}R}}$
(C) $\dfrac{\lambda }{{\pi {E_0}R}}$
(D) $\dfrac{1}{{2\pi {E_0}R}}$
Answer
269.7k+ views
Hint: The direction can be identified by seeing the distance or separation between the charges as: At exactly midway so the distance can be exactly half so here, the parallel infinite charges both positive and negative charges mean in the same direction.
Formula used:
Different formulas will be used to solve the problem which is mentioned below as:
$ {E_1} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}} \\
{E_2} = \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}} \\
$
Where R is distance between the separation
${E_0}$ Is epsilon value
E is the electrical field
$\lambda $ Is the positive and negative both are the infinite line charge
Complete Step by step answer:
As we know that a point charge is a hypothetical charge located at a single point in space.
And then the electric field is a vector. There are multiple point charges present. The net electric field at any point is the vector sum of the electric fields due to the individual charges.
By this image we can understand that separation R so as it’s at its exactly midway so we can take $\dfrac{R}{2}$ as their mid separation and this both the charges are in same direction
As parallel is given so both the direction will be same let be left to right
${E_1} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}}$ and ${E_2} = \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}}$
So, the net energy is,
${E_{net}} = {E_1} + {E_2}$
${E_{net}} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}} + \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}}$
$ \Rightarrow {E_{net}} = \dfrac{{2\lambda }}{{\pi {E_0}R}}$ So we get,
Hence the net electric field is: ${E_{net}} = \dfrac{{2\lambda }}{{\pi {E_0}R}}$
Hence the correct option is B that is $\dfrac{{2\lambda }}{{\pi {E_0}R}}$.
Note:
In question probably we get the hint so first we need to think about the direction of the charges. And then what is the distance of separation between the charges.
So first basically the electric field of an individual and then to get a total combining electric fields of the charges.
Formula used:
Different formulas will be used to solve the problem which is mentioned below as:
$ {E_1} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}} \\
{E_2} = \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}} \\
$
Where R is distance between the separation
${E_0}$ Is epsilon value
E is the electrical field
$\lambda $ Is the positive and negative both are the infinite line charge
Complete Step by step answer:
As we know that a point charge is a hypothetical charge located at a single point in space.
And then the electric field is a vector. There are multiple point charges present. The net electric field at any point is the vector sum of the electric fields due to the individual charges.
By this image we can understand that separation R so as it’s at its exactly midway so we can take $\dfrac{R}{2}$ as their mid separation and this both the charges are in same direction
As parallel is given so both the direction will be same let be left to right
${E_1} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}}$ and ${E_2} = \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}}$
So, the net energy is,
${E_{net}} = {E_1} + {E_2}$
${E_{net}} = \dfrac{\lambda }{{2\pi {E_0}\dfrac{R}{2}}} + \dfrac{{ - \lambda }}{{2\pi {E_0}\dfrac{R}{2}}}$
$ \Rightarrow {E_{net}} = \dfrac{{2\lambda }}{{\pi {E_0}R}}$ So we get,
Hence the net electric field is: ${E_{net}} = \dfrac{{2\lambda }}{{\pi {E_0}R}}$
Hence the correct option is B that is $\dfrac{{2\lambda }}{{\pi {E_0}R}}$.
Note:
In question probably we get the hint so first we need to think about the direction of the charges. And then what is the distance of separation between the charges.
So first basically the electric field of an individual and then to get a total combining electric fields of the charges.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Kinematics Mock Test for JEE Main 2025-26: Comprehensive Practice

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Marks vs Rank: Estimate IIT Rank from Your Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

