
Two normal uniform magnetic field contain a magnetic needle making an angle ${60^ \circ }$ with F. Then the ratio of $\dfrac{F}{H}$ is ?
A. $1:2$
B. $2:1$
C. $\sqrt 3 :1$
D. $1:\sqrt 3 $
Answer
162k+ views
Hint: We are aware that the Earth's magnetosphere is made up of the geomagnetic field, also known as the Earth's magnetic field, which effectively reaches into space for thousands of kilometres. Near the equator, when the field is horizontal, its strength is at its lowest. Gauss units are used to express the magnetic field's intensity.
Formula used:
$H = F\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Complete step by step solution:
We are aware that the portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as magnetic field strength, also known as magnetic intensity or magnetic field intensity.
We can also draw the conclusion that an angle is a measurement of how far an object is moving from its intended course. Measured between the line of sight to the target and the line of sight to the aiming point, the angle of a deflection shot in gunnery.

We know that $H = F\tan \theta $ where $\theta $ defines the angle through which the needle deflects.
So, at the equilibrium of needle we can say that putting$\theta = {60^ \circ }$
$\tan {60^ \circ } = \dfrac{H}{F}$
$ \Rightarrow \sqrt 3 = \dfrac{H}{F}$
$\therefore \dfrac{F}{H} = \dfrac{1}{{\sqrt 3 }}$
Hence the correct option is D.
Note: It is important to keep in mind the following facts about the magnetic field:
- There are two different types of magnetic fields: the B-field and the H-field.
- Teslas are used to measure B-field (T). A/m units are used to express the H-field.
- The earth's magnetic field is oriented so that it extends from its magnetic north pole to its magnetic south pole. The inclined bar magnet is merely a fictitious magnet; it does not exist.
Formula used:
$H = F\tan \theta $
where $\theta $ defines the angle through which the needle deflects.
Complete step by step solution:
We are aware that the portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as magnetic field strength, also known as magnetic intensity or magnetic field intensity.
We can also draw the conclusion that an angle is a measurement of how far an object is moving from its intended course. Measured between the line of sight to the target and the line of sight to the aiming point, the angle of a deflection shot in gunnery.

We know that $H = F\tan \theta $ where $\theta $ defines the angle through which the needle deflects.
So, at the equilibrium of needle we can say that putting$\theta = {60^ \circ }$
$\tan {60^ \circ } = \dfrac{H}{F}$
$ \Rightarrow \sqrt 3 = \dfrac{H}{F}$
$\therefore \dfrac{F}{H} = \dfrac{1}{{\sqrt 3 }}$
Hence the correct option is D.
Note: It is important to keep in mind the following facts about the magnetic field:
- There are two different types of magnetic fields: the B-field and the H-field.
- Teslas are used to measure B-field (T). A/m units are used to express the H-field.
- The earth's magnetic field is oriented so that it extends from its magnetic north pole to its magnetic south pole. The inclined bar magnet is merely a fictitious magnet; it does not exist.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

Young's Double Slit Experiment Step by Step Derivation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Wheatstone Bridge for JEE Main Physics 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Uniform Acceleration

Degree of Dissociation and Its Formula With Solved Example for JEE
