
The upper end of a wire $1\,m$ long and $2mm$ radius is clamped. The lower end is twisted through angle $45^\circ $. What is the angle of twist?
A. $0.009^\circ $
B. $0.09^\circ $
C. $0.9^\circ $
D. $9^\circ $
Answer
220.8k+ views
Hint: The torsion equation is used to compute the twist angle. A term used in the torsion equation to calculate the shaft length, rigidity modulus, and polar moment of inertia. The relationship between the angle of shear and the angle of twist must be used to calculate the angle of twist. We already have all the necessary data; after entering them into the formula, all we need to do is simplify and carry out some simple calculations to obtain the result.
Formula Used:
The relation between angle of shear, $\varphi $ and angle of twist, $\theta $ is given by the equation,
$r\theta = l\phi $
where, $r$ is the radius of wire and $l$ is the length of the wire.
Complete step by step solution:
In the question, we have given the radius of the wire $r = 2mm$ , length of the wire $l = 1m$ and angle of twist $\theta = 45^\circ $. Before solving the question, we need to convert all these values into their respective SI units. As we know that the SI unit of radius is metre. Hence, we will convert the radius into metres. We get, $r = 0.002m$
And, the relation between angle of shear, $\varphi $ and angle of twist, $\theta $ is given by the equation
$r\theta = l\phi $
Since the radius is very small. So, in this case on putting values in the formula, we get;
$0.002 \times 45 = 1 \times \phi $
Then, we have
$\phi = \dfrac{{0.002 \times 45}}{1}$
$\Rightarrow \phi = \dfrac{{2 \times {{10}^{ - 3}} \times 45}}{1}$
$\Rightarrow \phi = 0.002 \times 45$
$\therefore \phi = 0.09^\circ $
Therefore, the correct option is B.
Note: Make sure that all values are provided in SI units when answering questions like this. If not, then before using the specified values in the formula, convert them into SI units. If for any reason we do not convert the values into SI units, the result will be different. In this scenario, the response would have been different in just the decimal places if we hadn't remembered to convert the data into SI units. As a result, we would have seen the option in the answer and marked it as the correct one. Before utilising a value in a question, always convert it to SI units.
Formula Used:
The relation between angle of shear, $\varphi $ and angle of twist, $\theta $ is given by the equation,
$r\theta = l\phi $
where, $r$ is the radius of wire and $l$ is the length of the wire.
Complete step by step solution:
In the question, we have given the radius of the wire $r = 2mm$ , length of the wire $l = 1m$ and angle of twist $\theta = 45^\circ $. Before solving the question, we need to convert all these values into their respective SI units. As we know that the SI unit of radius is metre. Hence, we will convert the radius into metres. We get, $r = 0.002m$
And, the relation between angle of shear, $\varphi $ and angle of twist, $\theta $ is given by the equation
$r\theta = l\phi $
Since the radius is very small. So, in this case on putting values in the formula, we get;
$0.002 \times 45 = 1 \times \phi $
Then, we have
$\phi = \dfrac{{0.002 \times 45}}{1}$
$\Rightarrow \phi = \dfrac{{2 \times {{10}^{ - 3}} \times 45}}{1}$
$\Rightarrow \phi = 0.002 \times 45$
$\therefore \phi = 0.09^\circ $
Therefore, the correct option is B.
Note: Make sure that all values are provided in SI units when answering questions like this. If not, then before using the specified values in the formula, convert them into SI units. If for any reason we do not convert the values into SI units, the result will be different. In this scenario, the response would have been different in just the decimal places if we hadn't remembered to convert the data into SI units. As a result, we would have seen the option in the answer and marked it as the correct one. Before utilising a value in a question, always convert it to SI units.
Recently Updated Pages
Two discs which are rotating about their respective class 11 physics JEE_Main

A ladder rests against a frictionless vertical wall class 11 physics JEE_Main

Two simple pendulums of lengths 1 m and 16 m respectively class 11 physics JEE_Main

The slopes of isothermal and adiabatic curves are related class 11 physics JEE_Main

A trolly falling freely on an inclined plane as shown class 11 physics JEE_Main

The masses M1 and M2M2 M1 are released from rest Using class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

