The thermal capacity of \[40g\] of aluminium \[(s = 0.2cal/gK)\] is
(A) \[168J/K\]
(B) \[672J/K\]
(C) \[840J/K\]
(D) \[33.6J/K\]
Answer
262.2k+ views
Hint: Specific heat is the amount of energy required to raise the temperature per unit mass of a substance. The units will be Calories per Kelvin or Joules per Kelvin. Whereas, thermal capacity is the amount of energy required to raise the temperature. The units will be calories per Kelvin.
Complete Step by Step Solution:
Aluminium is a chemical element with an atomic number \[13\] and placed in a group\[IIIA\]. Some of the chemical elements will absorb heat energy and undergo differences in temperature. The amount of energy given to raise the temperature per unit mass of a substance is nothing but the specific heat capacity of that element. It is denoted by \[S\].
Given that specific heat capacity, \[S = 0.2cal/gK\]. It has the units of calories per gram kelvin.
Thermal capacity is also the same as specific heat capacity. But there is a difference in the mass calculation. Thermal capacity is the energy required to raise the temperature only but not per unit mass. Hence, it will have the units of Calories per Kelvin or Joules per Kelvin.
Thermal capacity will be \[ = 40g \times 0.2\dfrac{{Cal}}{{g.K}}\]
By solving the above equation, the thermal capacity will be \[S = 8Cal/K\].
But, in the given question the units of thermal capacity are Joules per Kelvin.
One calorie can be written as, \[1Cal = 4.184J\]
So, thermal capacity \[S = 8\dfrac{{Cal}}{K}*4.184\dfrac{J}{{1Cal}} = 33.6J/K\]
Therefore, the thermal capacity of \[40g\] of aluminium \[(s = 0.2cal/gK)\] is \[33.6J/K\]
Option d is the answer.
Note:Though both the specific heat capacity and thermal capacity represent the heat energy. The units were different. So, the units must be considered as grams or kilograms is mentioned or not, If the units of mass were mentioned, then it is specific heat capacity.
Complete Step by Step Solution:
Aluminium is a chemical element with an atomic number \[13\] and placed in a group\[IIIA\]. Some of the chemical elements will absorb heat energy and undergo differences in temperature. The amount of energy given to raise the temperature per unit mass of a substance is nothing but the specific heat capacity of that element. It is denoted by \[S\].
Given that specific heat capacity, \[S = 0.2cal/gK\]. It has the units of calories per gram kelvin.
Thermal capacity is also the same as specific heat capacity. But there is a difference in the mass calculation. Thermal capacity is the energy required to raise the temperature only but not per unit mass. Hence, it will have the units of Calories per Kelvin or Joules per Kelvin.
Thermal capacity will be \[ = 40g \times 0.2\dfrac{{Cal}}{{g.K}}\]
By solving the above equation, the thermal capacity will be \[S = 8Cal/K\].
But, in the given question the units of thermal capacity are Joules per Kelvin.
One calorie can be written as, \[1Cal = 4.184J\]
So, thermal capacity \[S = 8\dfrac{{Cal}}{K}*4.184\dfrac{J}{{1Cal}} = 33.6J/K\]
Therefore, the thermal capacity of \[40g\] of aluminium \[(s = 0.2cal/gK)\] is \[33.6J/K\]
Option d is the answer.
Note:Though both the specific heat capacity and thermal capacity represent the heat energy. The units were different. So, the units must be considered as grams or kilograms is mentioned or not, If the units of mass were mentioned, then it is specific heat capacity.
Recently Updated Pages
JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Notes Class 11 Chemistry Chapter 5 - Thermodynamics - 2025-26

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2025-26

