Question

The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time period of the vibration?

Answer 1

Hint: Period means the time taken by the waves to complete one cycle is known as the period. Here the vibration is given and they are asking the time period. So for this, we will use the formula of the time period to calculate.
Formula used
Time Period,
$ \Rightarrow T = \dfrac{1}{f}$
Where $T$is the time period and $f$is the frequency.

Solution
In wave mechanics, any given wave enfolds parameters like- frequency, period, wavelength, amplitude, etc. The period is the time taken by an entire cycle of the wave to pass a degree, Frequency is the variety of complete cycles of waves passing a degree in unit time.
 Angular frequency is the angular displacement of any part of the wave per unit of time. In curved wave motion, as shown on top of, the particles move regarding the mean equilibrium or mean position with the passage of our time. The particles rise until they reach the very best purpose that's the crest and so still fall until they reach the bottom purpose that's the trough.
So we have to find the time period so for this, we will put the required values in the equation.
$ \Rightarrow T = \dfrac{1}{f}$
Since $f = 500{\text{ vibrations / second}}$
Substituting the values in the formula we will get the time period
So,
\[ \Rightarrow T = \dfrac{1}{{500}}\sec \]
After calculation, we get
$ \Rightarrow 0.002{\text{ second}}$.
Therefore the time required will be$0.002{\text{ second}}$. And this is the required time period for the vibration.

Notes: Angular frequency is the angular displacement of any part of the wave per unit time. In curved wave motion, as shown on top of, the particles move regarding the mean equilibrium or mean position with the passage of our time.