
the resultant of two forces acting at an angle of $150{}^\circ$is $10N$ and its perpendicular to one of the forces. The two others force is:
(A) $\dfrac{20}{\sqrt{3}}N$
(B) $\dfrac{10}{\sqrt{3}}N$
(C) 20N
(D) $\dfrac{20}{3}N\,$
Answer
150.6k+ views
Hint: In physics, a vector is a quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the given quantity’s magnitude. Although a vector consists of magnitude and direction, it does not consist of a position. With this information in mind, we can easily solve such types of questions.
Complete step-by step answer:
Let the two forces mentioned in the above questions be A and B.
Let R be the resultant force of the force vectors A and B.
R is perpendicular in direction to the B vector.
We can determine from the given information that, $A\cos (60{}^\circ )=R=10\Rightarrow A=20N$
$\Rightarrow A\sin (60{}^\circ )=B\Rightarrow 10\sqrt{3}N$
$\therefore$Forces are 20N and $10\sqrt{3} N$.
Hence, the correct answer is Option C.
Note: We must keep in mind the various properties of a vector to be able to equate the given question. We must know how two vectors act when in parallel or perpendicular to each other.
Complete step-by step answer:
Let the two forces mentioned in the above questions be A and B.
Let R be the resultant force of the force vectors A and B.
R is perpendicular in direction to the B vector.
We can determine from the given information that, $A\cos (60{}^\circ )=R=10\Rightarrow A=20N$
$\Rightarrow A\sin (60{}^\circ )=B\Rightarrow 10\sqrt{3}N$
$\therefore$Forces are 20N and $10\sqrt{3} N$.
Hence, the correct answer is Option C.
Note: We must keep in mind the various properties of a vector to be able to equate the given question. We must know how two vectors act when in parallel or perpendicular to each other.
Recently Updated Pages
Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

JEE Main 2025 Helpline Numbers - Center Contact, Phone Number, Address

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

Electrical Field of Charged Spherical Shell - JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry
