
The P-V diagram of a diatomic ideal gas going under cyclic process as shown in the figure. The work done during an adiabatic process CD is (use \[\gamma \] =1.4):

(1) - 500 J
(2) - 400 J
(3) 400 J
(4) 200 J
Answer
222k+ views
Hint: An adiabatic process defines a process in thermodynamics where transferring of energy takes place without the transfer of mass or heat to the surrounding.
Formula used:
The formula for the work done is,
\[W = \dfrac{{{p_f}{v_f} - {p_i}{v_i}}}{{1 - \gamma }}\]
Here, W is work done, \[{p_f}\] is the final pressure, \[{p_i}\] is the initial pressure, \[{v_f}\] is the final volume and \[{v_i}\] is the initial volume.
Complete Step by Step Solution:
The Given diagram represents the adiabatic process of an ideal gas. From the graph, \[{p_i}\]is 100 N/m2 and \[{p_f}\]is 200 N/m2 . And \[{v_f}\]is 3 and \[{v_i}\]is 4 and \[\gamma \]is 1.4.
Putting all the above values in the formula of W.
So, work done in adiabatic process is,
\[\] \[{W_{CD}} = \dfrac{{200 \times 3 - 4 \times 100}}{{1 - 1.4}}\]
\[{W_{CD}} = \dfrac{{600 - 400}}{{ - 0.4}}\]
\[{W_{CD}} = - 500\,J\]
Hence, the work done in the given adiabatic process is -500 J. Therefore, option (1) is right
Additional Information:
Thermodynamics defines the studying of relations between work, energy, heat and temperature. The different thermodynamic law explains how the change of energy of a system takes place and whether the system has the ability to perform important work on the surroundings.
Note: There is the possibility of both reversibility or irreversibility of an adiabatic process. The necessary conditions required for the adiabatic process: (a)Perfect insulation of the system from the surrounding (b) The process should happen quickly so that there is enough time for the taking place of heat transfer.
Formula used:
The formula for the work done is,
\[W = \dfrac{{{p_f}{v_f} - {p_i}{v_i}}}{{1 - \gamma }}\]
Here, W is work done, \[{p_f}\] is the final pressure, \[{p_i}\] is the initial pressure, \[{v_f}\] is the final volume and \[{v_i}\] is the initial volume.
Complete Step by Step Solution:
The Given diagram represents the adiabatic process of an ideal gas. From the graph, \[{p_i}\]is 100 N/m2 and \[{p_f}\]is 200 N/m2 . And \[{v_f}\]is 3 and \[{v_i}\]is 4 and \[\gamma \]is 1.4.
Putting all the above values in the formula of W.
So, work done in adiabatic process is,
\[\] \[{W_{CD}} = \dfrac{{200 \times 3 - 4 \times 100}}{{1 - 1.4}}\]
\[{W_{CD}} = \dfrac{{600 - 400}}{{ - 0.4}}\]
\[{W_{CD}} = - 500\,J\]
Hence, the work done in the given adiabatic process is -500 J. Therefore, option (1) is right
Additional Information:
Thermodynamics defines the studying of relations between work, energy, heat and temperature. The different thermodynamic law explains how the change of energy of a system takes place and whether the system has the ability to perform important work on the surroundings.
Note: There is the possibility of both reversibility or irreversibility of an adiabatic process. The necessary conditions required for the adiabatic process: (a)Perfect insulation of the system from the surrounding (b) The process should happen quickly so that there is enough time for the taking place of heat transfer.
Recently Updated Pages
JEE Main 2022 (July 26th Shift 1) Physics Question Paper with Answer Key

JEE Main 2022 (June 26th Shift 2) Chemistry Question Paper with Answer Key

Apparent Frequency Explained: Formula, Uses & Examples

JEE Main 2023 (January 30th Shift 2) Chemistry Question Paper with Answer Key

Displacement Current and Maxwell’s Equations Explained

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

