
The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled, the reduction factor $\mathrm{K}$ will be :
A. remain same
B. be doubled
C. be quadrupled
D. be one fourth
Answer
162.6k+ views
Hint: An early measuring tool for measuring electric current is a tangent galvanometer. It operates by comparing the magnetic field produced by an unknown current to the magnetic field of the Earth using a compass needle. Current steadiness is measured using a tangent galvanometer.
Complete step by step solution:
We know that $i=\dfrac{2 \gamma B_{H}}{M_{0} n} \tan \theta$
$B_{H}=$ horizontal component
$\tan \theta=$ Angle of deflection
and we know that
$i=k \tan \theta$
A tangent galvanometer's reduction factor is measured in amperes. The tangent of the angle of the compass needle in a galvanometer is proportional to the relative strength of the two perpendicular magnetic fields, according to the tangent law of magnetism.
$K^{\prime} \rightarrow$ new reduction factor
$k^{\prime}=\dfrac{2 \times 2 \gamma \times B_{H}}{\mu_{0} \times 2 n}=k$
The new reduction factor, $k=k$
It remains same
Hence, the correct answer is option A.
Note: Tangent galvanometer is a device used for estimating current, and it is used to measure steady flows. It lowers the bar set by Tangent law. A beautiful needle strung at a location where two crossed fields are in right angles to one another will stop moving in the direction of the result of the two fields.
The magnetic field of Earth immediately causes the instrument needle to start moving.
Development continues until the plane of the loop and the earth's attractive field are aligned.
At that time, a second attractive field on the pivot of the loop that is opposed to the attractive field of the Earth is created using an unknown current.
As a result, the vector sum of the two fields triggers a response from the compass needle.
Complete step by step solution:
We know that $i=\dfrac{2 \gamma B_{H}}{M_{0} n} \tan \theta$
$B_{H}=$ horizontal component
$\tan \theta=$ Angle of deflection
and we know that
$i=k \tan \theta$
A tangent galvanometer's reduction factor is measured in amperes. The tangent of the angle of the compass needle in a galvanometer is proportional to the relative strength of the two perpendicular magnetic fields, according to the tangent law of magnetism.
$K^{\prime} \rightarrow$ new reduction factor
$k^{\prime}=\dfrac{2 \times 2 \gamma \times B_{H}}{\mu_{0} \times 2 n}=k$
The new reduction factor, $k=k$
It remains same
Hence, the correct answer is option A.
Note: Tangent galvanometer is a device used for estimating current, and it is used to measure steady flows. It lowers the bar set by Tangent law. A beautiful needle strung at a location where two crossed fields are in right angles to one another will stop moving in the direction of the result of the two fields.
The magnetic field of Earth immediately causes the instrument needle to start moving.
Development continues until the plane of the loop and the earth's attractive field are aligned.
At that time, a second attractive field on the pivot of the loop that is opposed to the attractive field of the Earth is created using an unknown current.
As a result, the vector sum of the two fields triggers a response from the compass needle.
Recently Updated Pages
Fluid Pressure - Important Concepts and Tips for JEE

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

Impulse Momentum Theorem Important Concepts and Tips for JEE

Graphical Methods of Vector Addition - Important Concepts for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Charging and Discharging of Capacitor

Wheatstone Bridge for JEE Main Physics 2025

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

In which of the following forms the energy is stored class 12 physics JEE_Main
