Question

The final product formed by the ozonolysis of compound $RCH=C{{R}_{2}}$ is
(A) $RCHO$
(B) ${{R}_{2}}CO$
(C) Both A and B
(D) None of these

Answer 1

Hint: The method of producing ozonides and then reducing them to produce carbonyl compounds is known as ozonolysis. By adding an ozone molecule to the double bond of alkenes or triple bond of alkynes, ozonides are created. The process of cleaving a double bond by creating a five-membered ring is known as ozonolysis. The ring has five members, three of which are oxygens, and two of which are carbons which were doubly bonded.

Complete Step by Step Answer:
The ozone molecule is added to the double bond of $RCH=C{{R}_{2}}$ in the ozonolysis reaction and forms an ozonide. Ozone (${{O}_{3}}$), a powerful oxidant, may easily transform alkenes into carbonyl compounds. Both the sigma and pi bonds are broken in this reaction. In the presence of $Zn/{{H}_{2}}O$, hydrolysis of the synthesised ozonide occurs.


One of the products formed is an aldehyde and the other is a ketone.
Hence, the final product formed by the ozonolysis of compound $RCH=C{{R}_{2}}$is $RCHO$ and${{R}_{2}}CO$.
Correct Option: (C) Both A and B.

Note: While symmetrical alkenes yield two moles of the same product molecule, unsymmetrical alkenes yield two moles of different molecules. This reaction can further produce carboxylic acids and alcohols. When an oxidizing agent is treated with the carbonyl compound formed in the above reaction, a carboxylic acid is formed. Similarly, when a reducing agent is treated with the carbonyl compound, an alcohol is formed.