
The electrochemical equivalent $\text{Z}$ of any element can be obtained by multiplying the electrochemical equivalent of hydrogen with
A. Atomic weight
B. Molecular weight
C. Chemical equivalent
D. A constant
Answer
222k+ views
Hint: According to Faraday’s second law of electrolysis, the electrochemical equivalent of a substance is directly proportional to its respective chemical equivalent. By using this law we can determine the value of the electrochemical equivalent, $Z$ of any element.
Formula used: Mathematical expression of Faraday’s second law is:
$\dfrac{{{\text{Z}}_{\text{1}}}}{{{\text{Z}}_{\text{2}}}}\text{=}\dfrac{{{\text{E}}_{\text{1}}}}{{{\text{E}}_{\text{2}}}}$
Here ${{Z}_{1}}\And {{Z}_{2}}$ are the electrochemical equivalent of substances $1\And 2$
${{E}_{1}}\And {{E}_{2}}$ are chemical equivalents of deposited substances$1\And 2$
Electrochemical equivalent,$Z=\dfrac{M}{F\times {{n}_{f}}}$
Here $M=$ Atomic weight of the deposited substance
$F=$ Faraday and ${{n}_{f}}=$ n-factor
Complete Step by Step Answer:
The electrochemical equivalent is defined by the mass of a chemical substance deposited or evolved during the process of electrolysis by the passage of a certain amount of current and it is usually expressed in grams per coulomb.
Let another element is $X$
According to Faraday’s second law of electrolysis, $\dfrac{{{Z}_{X}}}{{{Z}_{H}}}=\dfrac{{{E}_{X}}}{{{E}_{H}}}$
${{Z}_{X}}=\dfrac{{{E}_{H}}}{{{E}_{X}}}\times {{Z}_{H}}$
The electrochemical equivalent of any other element(X) is obtained by multiplying the electrochemical equivalent of Hydrogen with the chemical equivalent.
Thus, the correct option is (C).
Additional information: Electrolysis is a method in which electrical energy is converted to chemical energy through a chemical reaction. The electrolysis process is used widely in metallurgical processes for example purification or extraction of metals from ores and deposition of metals from solution. Other applications of electrolysis are electroplating, manufacturing of chemicals, electro-deposition of rubber, electro-facing, anodizing, etc.
Note: Faraday’s law of electrolysis is used to express quantitative magnitudes of electrolytic effects. Faraday’s second law of electrolysis is very useful for the calculation of chemical equivalents of different electrolysis. During the electrolysis process, the amount of substances oxidized or reduced at the respective electrodes.
Formula used: Mathematical expression of Faraday’s second law is:
$\dfrac{{{\text{Z}}_{\text{1}}}}{{{\text{Z}}_{\text{2}}}}\text{=}\dfrac{{{\text{E}}_{\text{1}}}}{{{\text{E}}_{\text{2}}}}$
Here ${{Z}_{1}}\And {{Z}_{2}}$ are the electrochemical equivalent of substances $1\And 2$
${{E}_{1}}\And {{E}_{2}}$ are chemical equivalents of deposited substances$1\And 2$
Electrochemical equivalent,$Z=\dfrac{M}{F\times {{n}_{f}}}$
Here $M=$ Atomic weight of the deposited substance
$F=$ Faraday and ${{n}_{f}}=$ n-factor
Complete Step by Step Answer:
The electrochemical equivalent is defined by the mass of a chemical substance deposited or evolved during the process of electrolysis by the passage of a certain amount of current and it is usually expressed in grams per coulomb.
Let another element is $X$
According to Faraday’s second law of electrolysis, $\dfrac{{{Z}_{X}}}{{{Z}_{H}}}=\dfrac{{{E}_{X}}}{{{E}_{H}}}$
${{Z}_{X}}=\dfrac{{{E}_{H}}}{{{E}_{X}}}\times {{Z}_{H}}$
The electrochemical equivalent of any other element(X) is obtained by multiplying the electrochemical equivalent of Hydrogen with the chemical equivalent.
Thus, the correct option is (C).
Additional information: Electrolysis is a method in which electrical energy is converted to chemical energy through a chemical reaction. The electrolysis process is used widely in metallurgical processes for example purification or extraction of metals from ores and deposition of metals from solution. Other applications of electrolysis are electroplating, manufacturing of chemicals, electro-deposition of rubber, electro-facing, anodizing, etc.
Note: Faraday’s law of electrolysis is used to express quantitative magnitudes of electrolytic effects. Faraday’s second law of electrolysis is very useful for the calculation of chemical equivalents of different electrolysis. During the electrolysis process, the amount of substances oxidized or reduced at the respective electrodes.
Recently Updated Pages
Types of Solutions in Chemistry: Explained Simply

States of Matter Chapter For JEE Main Chemistry

Know The Difference Between Fluid And Liquid

Difference Between Crystalline and Amorphous Solid: Table & Examples

Conduction Explained: Definition, Examples & Science for Students

Balancing of Redox Reactions - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

