The electrochemical equivalent $\text{Z}$ of any element can be obtained by multiplying the electrochemical equivalent of hydrogen with
A. Atomic weight
B. Molecular weight
C. Chemical equivalent
D. A constant
Answer
252.9k+ views
Hint: According to Faraday’s second law of electrolysis, the electrochemical equivalent of a substance is directly proportional to its respective chemical equivalent. By using this law we can determine the value of the electrochemical equivalent, $Z$ of any element.
Formula used: Mathematical expression of Faraday’s second law is:
$\dfrac{{{\text{Z}}_{\text{1}}}}{{{\text{Z}}_{\text{2}}}}\text{=}\dfrac{{{\text{E}}_{\text{1}}}}{{{\text{E}}_{\text{2}}}}$
Here ${{Z}_{1}}\And {{Z}_{2}}$ are the electrochemical equivalent of substances $1\And 2$
${{E}_{1}}\And {{E}_{2}}$ are chemical equivalents of deposited substances$1\And 2$
Electrochemical equivalent,$Z=\dfrac{M}{F\times {{n}_{f}}}$
Here $M=$ Atomic weight of the deposited substance
$F=$ Faraday and ${{n}_{f}}=$ n-factor
Complete Step by Step Answer:
The electrochemical equivalent is defined by the mass of a chemical substance deposited or evolved during the process of electrolysis by the passage of a certain amount of current and it is usually expressed in grams per coulomb.
Let another element is $X$
According to Faraday’s second law of electrolysis, $\dfrac{{{Z}_{X}}}{{{Z}_{H}}}=\dfrac{{{E}_{X}}}{{{E}_{H}}}$
${{Z}_{X}}=\dfrac{{{E}_{H}}}{{{E}_{X}}}\times {{Z}_{H}}$
The electrochemical equivalent of any other element(X) is obtained by multiplying the electrochemical equivalent of Hydrogen with the chemical equivalent.
Thus, the correct option is (C).
Additional information: Electrolysis is a method in which electrical energy is converted to chemical energy through a chemical reaction. The electrolysis process is used widely in metallurgical processes for example purification or extraction of metals from ores and deposition of metals from solution. Other applications of electrolysis are electroplating, manufacturing of chemicals, electro-deposition of rubber, electro-facing, anodizing, etc.
Note: Faraday’s law of electrolysis is used to express quantitative magnitudes of electrolytic effects. Faraday’s second law of electrolysis is very useful for the calculation of chemical equivalents of different electrolysis. During the electrolysis process, the amount of substances oxidized or reduced at the respective electrodes.
Formula used: Mathematical expression of Faraday’s second law is:
$\dfrac{{{\text{Z}}_{\text{1}}}}{{{\text{Z}}_{\text{2}}}}\text{=}\dfrac{{{\text{E}}_{\text{1}}}}{{{\text{E}}_{\text{2}}}}$
Here ${{Z}_{1}}\And {{Z}_{2}}$ are the electrochemical equivalent of substances $1\And 2$
${{E}_{1}}\And {{E}_{2}}$ are chemical equivalents of deposited substances$1\And 2$
Electrochemical equivalent,$Z=\dfrac{M}{F\times {{n}_{f}}}$
Here $M=$ Atomic weight of the deposited substance
$F=$ Faraday and ${{n}_{f}}=$ n-factor
Complete Step by Step Answer:
The electrochemical equivalent is defined by the mass of a chemical substance deposited or evolved during the process of electrolysis by the passage of a certain amount of current and it is usually expressed in grams per coulomb.
Let another element is $X$
According to Faraday’s second law of electrolysis, $\dfrac{{{Z}_{X}}}{{{Z}_{H}}}=\dfrac{{{E}_{X}}}{{{E}_{H}}}$
${{Z}_{X}}=\dfrac{{{E}_{H}}}{{{E}_{X}}}\times {{Z}_{H}}$
The electrochemical equivalent of any other element(X) is obtained by multiplying the electrochemical equivalent of Hydrogen with the chemical equivalent.
Thus, the correct option is (C).
Additional information: Electrolysis is a method in which electrical energy is converted to chemical energy through a chemical reaction. The electrolysis process is used widely in metallurgical processes for example purification or extraction of metals from ores and deposition of metals from solution. Other applications of electrolysis are electroplating, manufacturing of chemicals, electro-deposition of rubber, electro-facing, anodizing, etc.
Note: Faraday’s law of electrolysis is used to express quantitative magnitudes of electrolytic effects. Faraday’s second law of electrolysis is very useful for the calculation of chemical equivalents of different electrolysis. During the electrolysis process, the amount of substances oxidized or reduced at the respective electrodes.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Types of Solutions in Chemistry: Explained Simply

Difference Between Crystalline and Amorphous Solid: Table & Examples

Know The Difference Between Fluid And Liquid

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

[Awaiting the three content sources: Ask AI Response, Competitor 1 Content, and Competitor 2 Content. Please provide those to continue with the analysis and optimization.]

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Notes Class 11 Chemistry Chapter 9 - Hydrocarbons - 2025-26

CBSE Notes Class 11 Chemistry Chapter 5 - Thermodynamics - 2025-26

CBSE Notes Class 11 Chemistry Chapter 8 - Organic Chemistry Some Basic Principles And Techniques - 2025-26

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

