The dimensions of electromotive force in terms of current $A$ are:
A) $\left[ {M{L^{ - 2}}{A^{ - 2}}} \right]$
B) $\left[ {M{L^2}{T^{ - 2}}{A^2}} \right]$
C) $\left[ {M{L^2}{T^{ - 2}}{A^{ - 2}}} \right]$
D) $\left[ {M{L^2}{T^{ - 3}}{A^{ - 1}}} \right]$
Answer
249.9k+ views
Hint: To solve this question we should know about the base quantities which are used to form the dimensional formulae of any quantity. Also we should know how electromotive force is calculated i.e., the quantities involved in its calculation and their dimensional formulae.
Formulae used:
$V = \dfrac{W}{q}$
Here $V$ is the potential difference across the cell or the electromotive force of the cell, $W$ is the work done by the charge and $q$ is the charge.
Complete answer:
To solve this question we should know what electromotive force is. Electromotive force or the EMF, for short, of a cell is defined as the electric potential produced either by an electrochemical cell or by changing the magnetic field.
We know that,
$V = \dfrac{W}{q}$
Here $V$ is the potential difference across the cell or the electromotive force of the cell, $W$ is the work done by the charge and $q$ is the charge.
Let this be equation 1.
The potential difference gives us the value of the electromotive force or EMF of a cell. So,
$ \Rightarrow V = \dfrac{W}{q}$
Let this be equation 1.
This will give the value of electromotive force or EMF of a cell.
We know that the dimensional formulae of
$\left[ q \right] = \left[ {AT} \right]$
$\left[ W \right] = \left[ {M{L^2}{T^{ - 2}}} \right]$
Substituting the values of the above quantities in the equation 1 we get,
$ \Rightarrow \left[ V \right] = \dfrac{{\left[ {M{L^2}{T^{ - 2}}} \right]}}{{\left[ {AT} \right]}}$
$ \Rightarrow \left[ V \right] = \left[ {M{L^2}{T^{ - 3}}{A^{ - 1}}} \right]$
So the answer will be option (D).
Note: To solve questions related to dimensional analysis of any quantity, break the quantity into its smaller known units. Use the dimensional formulae of the smaller known units to find the dimensional formulae of the given quantity. Electromotive force is the energy per unit electric charge. It is the force driving all electrons. Flow of electrons is due to this force.
Formulae used:
$V = \dfrac{W}{q}$
Here $V$ is the potential difference across the cell or the electromotive force of the cell, $W$ is the work done by the charge and $q$ is the charge.
Complete answer:
To solve this question we should know what electromotive force is. Electromotive force or the EMF, for short, of a cell is defined as the electric potential produced either by an electrochemical cell or by changing the magnetic field.
We know that,
$V = \dfrac{W}{q}$
Here $V$ is the potential difference across the cell or the electromotive force of the cell, $W$ is the work done by the charge and $q$ is the charge.
Let this be equation 1.
The potential difference gives us the value of the electromotive force or EMF of a cell. So,
$ \Rightarrow V = \dfrac{W}{q}$
Let this be equation 1.
This will give the value of electromotive force or EMF of a cell.
We know that the dimensional formulae of
$\left[ q \right] = \left[ {AT} \right]$
$\left[ W \right] = \left[ {M{L^2}{T^{ - 2}}} \right]$
Substituting the values of the above quantities in the equation 1 we get,
$ \Rightarrow \left[ V \right] = \dfrac{{\left[ {M{L^2}{T^{ - 2}}} \right]}}{{\left[ {AT} \right]}}$
$ \Rightarrow \left[ V \right] = \left[ {M{L^2}{T^{ - 3}}{A^{ - 1}}} \right]$
So the answer will be option (D).
Note: To solve questions related to dimensional analysis of any quantity, break the quantity into its smaller known units. Use the dimensional formulae of the smaller known units to find the dimensional formulae of the given quantity. Electromotive force is the energy per unit electric charge. It is the force driving all electrons. Flow of electrons is due to this force.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Understanding the Angle of Deviation in a Prism

Understanding Centrifugal Force in Physics

