Answer
Verified
91.2k+ views
Hint: A short trick to identify the hybridization of an atom is to count the total atoms attached to the atom and the number of lone pairs surrounding the atom. If the counts are 4,3,2, the hybridizations are \[s{p^3}\], \[s{p^2}\] and sp respectively.
Complete Step by Step Answer:
Here, we have to find out the hydrocarbon that has both sp and \[s{p^2}\]hybridised atoms of carbon.
Let's check all the options one by one.
Option A is propene. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_{\rm{3}}}}\limits_{s{p^3}} - \mathop {{\rm{CH}}}\limits_{s{p^2}} = \mathop {C{H_2}}\limits_{s{p^2}} \] . C1 is \[s{p^3}\] hybridised as it forms a bond with four groups, C2 is \[s{p^2}\]hybridised as it forms a bond with three groups and C3 is \[sp\] hybridised as it forms a bond with two groups. So, no sp hybridised carbon is present in the compound.
Option B is propyne. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_{\rm{3}}}}\limits_{s{p^3}} - \mathop {\rm{C}}\limits_{sp} \equiv \mathop {{\rm{CH}}}\limits_{sp} \]. C1 is \[s{p^3}\] hybridised as it forms a bond with four groups, C2 is \[sp\]hybridised as it forms a bond with two groups and C3 is \[sp\] hybridised as it forms a bond with two groups. So, no \[s{p^2}\]hybridised carbon is present in the compound.
Option C is propadiene. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_2}}\limits_{s{p^2}} = \mathop {\rm{C}}\limits_{sp} = \mathop {{\rm{C}}{{\rm{H}}_{\rm{2}}}}\limits_{s{p^2}} \] .C1 is \[s{p^2}\] hybridised as it forms bond with three groups, C2 is \[sp\]hybridised as it forms bond with two groups and C3 is \[s{p^2}\] hybridised as it forms bond with three groups. So, both sp and\[s{p^2}\]hybridised carbon atoms are present in the compound.
Therefore, option C is right.
Note: It is to be noted that, the count of lone pairs surrounding an atom should also be counted while identifying the type of hybridization. In the given questions, no lone pairs are present in any of these compounds, so the count of lone pairs is not needed.
Complete Step by Step Answer:
Here, we have to find out the hydrocarbon that has both sp and \[s{p^2}\]hybridised atoms of carbon.
Let's check all the options one by one.
Option A is propene. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_{\rm{3}}}}\limits_{s{p^3}} - \mathop {{\rm{CH}}}\limits_{s{p^2}} = \mathop {C{H_2}}\limits_{s{p^2}} \] . C1 is \[s{p^3}\] hybridised as it forms a bond with four groups, C2 is \[s{p^2}\]hybridised as it forms a bond with three groups and C3 is \[sp\] hybridised as it forms a bond with two groups. So, no sp hybridised carbon is present in the compound.
Option B is propyne. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_{\rm{3}}}}\limits_{s{p^3}} - \mathop {\rm{C}}\limits_{sp} \equiv \mathop {{\rm{CH}}}\limits_{sp} \]. C1 is \[s{p^3}\] hybridised as it forms a bond with four groups, C2 is \[sp\]hybridised as it forms a bond with two groups and C3 is \[sp\] hybridised as it forms a bond with two groups. So, no \[s{p^2}\]hybridised carbon is present in the compound.
Option C is propadiene. Its structure is \[\mathop {{\rm{C}}{{\rm{H}}_2}}\limits_{s{p^2}} = \mathop {\rm{C}}\limits_{sp} = \mathop {{\rm{C}}{{\rm{H}}_{\rm{2}}}}\limits_{s{p^2}} \] .C1 is \[s{p^2}\] hybridised as it forms bond with three groups, C2 is \[sp\]hybridised as it forms bond with two groups and C3 is \[s{p^2}\] hybridised as it forms bond with three groups. So, both sp and\[s{p^2}\]hybridised carbon atoms are present in the compound.
Therefore, option C is right.
Note: It is to be noted that, the count of lone pairs surrounding an atom should also be counted while identifying the type of hybridization. In the given questions, no lone pairs are present in any of these compounds, so the count of lone pairs is not needed.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
Other Pages
Derive an expression for maximum speed of a car on class 11 physics JEE_Main
The vapour pressure of pure A is 10 torr and at the class 12 chemistry JEE_Main
Velocity of car at t 0 is u moves with a constant acceleration class 11 physics JEE_Main
3 mole of gas X and 2 moles of gas Y enters from the class 11 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
If the distance between 1st crest and the third crest class 11 physics JEE_Main