
The amount of heat energy required to raise the temperature of $1g$ of Helium at NTP, from ${T_1}K$ to ${T_2}K$ is ?
A) $\dfrac{3}{2}{N_a}{K_B}\left( {{T_2} - {T_1}} \right)$
B) $\dfrac{3}{4}{N_a}{K_B}\left( {{T_2} - {T_1}} \right)$
C) $\dfrac{3}{4}{N_a}{K_B}\left( {\dfrac{{{T_2}}}{{{T_1}}}} \right)$
D) $\dfrac{3}{8}{N_a}{K_B}\left( {{T_2} - {T_1}} \right)$
Answer
233.1k+ views
Hint: For solving this question the mass of the $He$ is given in the equation and we know that molar mass of the $He$ is $4g/mol$ by this we get the number of moles of $He$ . And specific heat at constant volume is $\dfrac{3}{2}R$ and then change in temperature that is $\Delta T = {T_2} - {T_1}$ , by putting all these values in $\Delta \theta = n{C_v}\Delta T$ we get the heat required.
Complete step by step answer:
We know that,
Heat is defined as it is form of energy which is used to transfer Kinetic energy from medium or object to another this is known as Heat.
Mass of $He = 1gm$
Molar mass of $He = 4g/mol$
No of moles of the heat$ = \dfrac{m}{M}$
$ = \dfrac{1}{4}mol$
And given rising temperature will be $\Delta T = {T_2} - {T_1}$
Temperature is defined as it is a physical quantity that is used to express hot and cold means whether the temperature is hot or cold. This is known as Temperature.
So, the value of ${C_v}$ for Helium is
And ${C_v} = \dfrac{3}{2}R$ because it is monoatomic gas.
Now, $\Delta Q = n{C_v}\Delta T$
Now, putting the values.
$ = \dfrac{1}{4} \times \dfrac{3}{2}R \times \left( {{T_2} - {T_1}} \right)$
$ = \dfrac{3}{8}R\left( {{T_2} - {T_1}} \right)$
Now, substituting the value.
$ = \dfrac{3}{8}{N_a}{K_B}\left( {{T_2} - {T_1}} \right)$
Where $R = $Boltzmann constant ${K_B}$ $ \times $ Avogadro number ${N_a}$
Boltzmann constant is defined as it is a type of physical constant that relates a particle energy with temperature.
Avogadro number is defined as it is an absolute number. The number of units in one mole for any substance is known as Avogadro number.
Which means $R = {{\rm K}_B} \times {N_a}$
Hence, the correct option is D.
Note: It is important to consider 1g of helium instead of 1mole of Helium in this question as mentioned as it can lead to calculation error. Also the equations in kinetic theory of gases are only valid for ideal gases.
Complete step by step answer:
We know that,
Heat is defined as it is form of energy which is used to transfer Kinetic energy from medium or object to another this is known as Heat.
Mass of $He = 1gm$
Molar mass of $He = 4g/mol$
No of moles of the heat$ = \dfrac{m}{M}$
$ = \dfrac{1}{4}mol$
And given rising temperature will be $\Delta T = {T_2} - {T_1}$
Temperature is defined as it is a physical quantity that is used to express hot and cold means whether the temperature is hot or cold. This is known as Temperature.
So, the value of ${C_v}$ for Helium is
And ${C_v} = \dfrac{3}{2}R$ because it is monoatomic gas.
Now, $\Delta Q = n{C_v}\Delta T$
Now, putting the values.
$ = \dfrac{1}{4} \times \dfrac{3}{2}R \times \left( {{T_2} - {T_1}} \right)$
$ = \dfrac{3}{8}R\left( {{T_2} - {T_1}} \right)$
Now, substituting the value.
$ = \dfrac{3}{8}{N_a}{K_B}\left( {{T_2} - {T_1}} \right)$
Where $R = $Boltzmann constant ${K_B}$ $ \times $ Avogadro number ${N_a}$
Boltzmann constant is defined as it is a type of physical constant that relates a particle energy with temperature.
Avogadro number is defined as it is an absolute number. The number of units in one mole for any substance is known as Avogadro number.
Which means $R = {{\rm K}_B} \times {N_a}$
Hence, the correct option is D.
Note: It is important to consider 1g of helium instead of 1mole of Helium in this question as mentioned as it can lead to calculation error. Also the equations in kinetic theory of gases are only valid for ideal gases.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

