
What is the solution of the differential equation \[\cot ydx = xdy\]?
A. \[y = \cos x\]
B. \[x = c\sec y\]
C. \[x = \sin y\]
D. \[y = \sin x\]
Answer
216.3k+ views
Hint: First we will separate the variables of the differential equation. Then we will integrate both sides of the differential equation to get the solution. By using the logarithm formula we will simplify the solution.
Formula Used: Integrating formula:
\[\int {\tan \theta d\theta } = \log \sec \theta + c\]
\[\int {\dfrac{1}{x}dx} = \log x + c\]
Product formula for logarithm:
\[\log a + \log b = \log ab\]
Complete step by step solution: Given differential equation is
\[\cot ydx = xdy\]
Separate the variables of the differential equation:
\[ \Rightarrow \dfrac{{dx}}{x} = \dfrac{{dy}}{{\cot y}}\]
\[ \Rightarrow \dfrac{{dx}}{x} = \tan ydy\]
Taking integration on both sides:
\[ \Rightarrow \int {\dfrac{{dx}}{x}} = \int {\tan ydy} \]
Applying integration formula:
\[ \Rightarrow \log x = \log \sec y + \log c\]
Applying the product rule of logarithm:
\[ \Rightarrow \log x = \log c\sec y\]
Applying the antilogarithm formula:
\[ \Rightarrow x = c\sec y\]
Option ‘B’ is correct
Additional Information: The constant that is added with the result of the integration is known as the integration constant. Usually, the integration constant denotes by c. Using antiderivative we are unable to get the actual expression. Thus we add an integration constant with the result of integration to get the family of solutions of the differential equation.
A solution of a differential equation is known as the general solution if the value of the constant is unknown.
Note: Students often do mistake to integrating \[\tan ydy\]. They used a wrong formula that is \[\int {\tan \theta d\theta } = \log \cos \theta + c\]. The correct formula is \[\int {\tan \theta d\theta } = \log \sec \theta + c\].
Formula Used: Integrating formula:
\[\int {\tan \theta d\theta } = \log \sec \theta + c\]
\[\int {\dfrac{1}{x}dx} = \log x + c\]
Product formula for logarithm:
\[\log a + \log b = \log ab\]
Complete step by step solution: Given differential equation is
\[\cot ydx = xdy\]
Separate the variables of the differential equation:
\[ \Rightarrow \dfrac{{dx}}{x} = \dfrac{{dy}}{{\cot y}}\]
\[ \Rightarrow \dfrac{{dx}}{x} = \tan ydy\]
Taking integration on both sides:
\[ \Rightarrow \int {\dfrac{{dx}}{x}} = \int {\tan ydy} \]
Applying integration formula:
\[ \Rightarrow \log x = \log \sec y + \log c\]
Applying the product rule of logarithm:
\[ \Rightarrow \log x = \log c\sec y\]
Applying the antilogarithm formula:
\[ \Rightarrow x = c\sec y\]
Option ‘B’ is correct
Additional Information: The constant that is added with the result of the integration is known as the integration constant. Usually, the integration constant denotes by c. Using antiderivative we are unable to get the actual expression. Thus we add an integration constant with the result of integration to get the family of solutions of the differential equation.
A solution of a differential equation is known as the general solution if the value of the constant is unknown.
Note: Students often do mistake to integrating \[\tan ydy\]. They used a wrong formula that is \[\int {\tan \theta d\theta } = \log \cos \theta + c\]. The correct formula is \[\int {\tan \theta d\theta } = \log \sec \theta + c\].
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

Understanding Atomic Structure for Beginners

NCERT Solutions For Class 11 Maths Chapter 12 Limits And Derivatives

