Question

Solubility product for sodium chloride is $36$ M. The solubility of sodium chloride is :
A. $6M$
B. $\frac{1}{6}M$
C. $\frac{1}{36}$ M
D. $3600$ M

Answer 1

Hint: Solubility product depends on the number of ions formed in a reaction at equilibrium. $NaCl$ or sodium chloride dissociate into one sodium cation and one chloride anion.

Complete Step by Step Answer:
Solubility product of a species is defined as the product of the concentration of the cation and anion formed from a species at equilibrium. At this stage the coefficients before the ions exist as a power to the concentration of the corresponding cation and anion.

Sodium chloride dissociate at equilibrium as follows:
$NaCl\rightleftharpoons N{{a}^{+}}+C{{l}^{-}}$
Thus sodium chloride dissociates into one sodium cation and one chlorine anion at equilibrium.

Thus solubility product is given as follows:
$K_{sp}=(S)\times S$; Where $K_{sp}$ is defined as the solubility product and $S$ is defined as the solubility for the cation and anion. Sodium chloride has a coefficient of one before its cation and anion.
The value of solubility product is $36$ M. Putting the value of solubility product in the above equation we get:
$36={{S}^{2}}$
$S=6M$
Thus the value of solubility of sodium chloride is $6M$ .
Thus the correct option is A.

Note: Sodium chloride is an ionic compound. It dissociates into the corresponding ions in solution state. It is a white colored solid and it is highly soluble in water.