
Sodium chloride, when heated with conc. Sulfuric acid and solid potassium dichromate gives :
A. Chromic chloride
B. Chromyl chloride
C. Chromous chloride
D. None of these
Answer
161.4k+ views
Hint: To answer this question we have to know about the reaction of sodium chloride with sulfuric acid and potassium dichromate. Sodium chloride reacts with hot and concentrated sulfuric acid and potassium dichromate to form chromyl chloride as major product.
Complete Step by Step Answer:
The sodium salt of chlorine that is Sodium chloride reacts with a hot and concentrated strong acid that is sulfuric acid and a strong oxidising agent that is potassium dichromate to form chromyl chloride as the major product along with a potassium salt of chlorine that is potassium chloride , water and a salt of sodium that is sodium bisulfate as the minor or side products.
Thus the reaction of sodium chloride with sulfuric acid and potassium dichromate can be given as follows:
$NaCl+{{H}_{2}}S{{O}_{4}}+{{K}_{2}}C{{r}_{2}}{{O}_{7}}\to KCl+N{{a}_{2}}S{{O}_{4}}+Cr{{O}_{2}}C{{l}_{2}}+{{H}_{2}}O$
The chemical name of \[Cr{{O}_{2}}C{{l}_{2}}\] is chromyl chloride. Thus we can write that Sodium chloride, when heated with conc. Sulfuric acid and solid potassium dichromate gives chromyl chloride.
Thus the correct option is B.
Note: In this reaction potassium dichromate is a strong oxidising agent which helps to oxidise other species and reduce itself. This reaction forms chromyl chloride as a major product along with three side products.
Complete Step by Step Answer:
The sodium salt of chlorine that is Sodium chloride reacts with a hot and concentrated strong acid that is sulfuric acid and a strong oxidising agent that is potassium dichromate to form chromyl chloride as the major product along with a potassium salt of chlorine that is potassium chloride , water and a salt of sodium that is sodium bisulfate as the minor or side products.
Thus the reaction of sodium chloride with sulfuric acid and potassium dichromate can be given as follows:
$NaCl+{{H}_{2}}S{{O}_{4}}+{{K}_{2}}C{{r}_{2}}{{O}_{7}}\to KCl+N{{a}_{2}}S{{O}_{4}}+Cr{{O}_{2}}C{{l}_{2}}+{{H}_{2}}O$
The chemical name of \[Cr{{O}_{2}}C{{l}_{2}}\] is chromyl chloride. Thus we can write that Sodium chloride, when heated with conc. Sulfuric acid and solid potassium dichromate gives chromyl chloride.
Thus the correct option is B.
Note: In this reaction potassium dichromate is a strong oxidising agent which helps to oxidise other species and reduce itself. This reaction forms chromyl chloride as a major product along with three side products.
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