
Select the correct order of basic nature:
A. $C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C^ - } > O{H^ - }$
B. $C{H_3}C{H^ - }_2 > CH \equiv {C^ - } > C{H_2} = C{H^ - } > O{H^ - }$
C. $C{H_3}C{H^ - }_2 > O{H^ - } > CH \equiv {C^ - } > C{H_2} = C{H^ - }$
D. $O{H^ - } > CH \equiv {C^ - } > C{H_2} = C{H^ - } > C{H_3}C{H^ - }_2$
Answer
126.3k+ views
Hint: We can approach this problem by finding out the acidic nature of the compounds and then we will get order of the basic nature of the ions. We know that the conjugate base is obtained by removing a proton from a compound.
Complete step by step solution:
> The given ions are $C{H_3}C{H^ - }_2,C{H_2} = C{H^ - },CH \equiv {C^ - }$ and $O{H^ - }$. On addition of a proton $\left( {{H^ + }} \right)$ to the given ions we have found that these compounds are $C{H_3}C{H_3},C{H_2} = C{H_2},CH \equiv CH$ and ${H_2}O$. So we can find the order of acidic nature of the compounds. We know that a hydrogen tends to be acidic when it is attached to an electronegative atom or we can say that the conjugate base will be more stable on the localization of the negative charge on a more electronegative atom. The acidic nature of alkanes , alkenes and alkyne depends on the percentage s character. Alkanes used to be $s{p^3}$ hybridized so they have $25\% $ s-character similarly alkene possess $33.3\% $ s- character and alkynes possess $50\% $ s- characters. So their order of acidity is Alkynes > alkenes> Alkanes. Water will have less acidic nature than alkane, alkene and alkyne. Hence the order of acidic strength of the given compounds are ${H_2}O > CH \equiv CH > C{H_2} = C{H_2} > C{H_3}C{H_3}$. We have studied that the conjugate base of a strong acid will be weak so the order of the given conjugate bases of the compounds will be $C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C^ - } > O{H^ - }$. Hence option A is the correct order of basic nature.
Note: We know that the conjugate base of a stronger acid used to be a weak base and vice versa so here we have found the order of acidic nature of the given compounds and that order gives us the order of basic nature of compounds.
Complete step by step solution:
> The given ions are $C{H_3}C{H^ - }_2,C{H_2} = C{H^ - },CH \equiv {C^ - }$ and $O{H^ - }$. On addition of a proton $\left( {{H^ + }} \right)$ to the given ions we have found that these compounds are $C{H_3}C{H_3},C{H_2} = C{H_2},CH \equiv CH$ and ${H_2}O$. So we can find the order of acidic nature of the compounds. We know that a hydrogen tends to be acidic when it is attached to an electronegative atom or we can say that the conjugate base will be more stable on the localization of the negative charge on a more electronegative atom. The acidic nature of alkanes , alkenes and alkyne depends on the percentage s character. Alkanes used to be $s{p^3}$ hybridized so they have $25\% $ s-character similarly alkene possess $33.3\% $ s- character and alkynes possess $50\% $ s- characters. So their order of acidity is Alkynes > alkenes> Alkanes. Water will have less acidic nature than alkane, alkene and alkyne. Hence the order of acidic strength of the given compounds are ${H_2}O > CH \equiv CH > C{H_2} = C{H_2} > C{H_3}C{H_3}$. We have studied that the conjugate base of a strong acid will be weak so the order of the given conjugate bases of the compounds will be $C{H_3}C{H^ - }_2 > C{H_2} = C{H^ - } > CH \equiv {C^ - } > O{H^ - }$. Hence option A is the correct order of basic nature.
Note: We know that the conjugate base of a stronger acid used to be a weak base and vice versa so here we have found the order of acidic nature of the given compounds and that order gives us the order of basic nature of compounds.
Recently Updated Pages
JEE Main 2023 (January 30th Shift 2) Maths Question Paper with Answer Key

Know The Difference Between Fluid And Liquid

JEE Main 2022 (July 25th Shift 2) Physics Question Paper with Answer Key

Classification of Elements and Periodicity in Properties Chapter For JEE Main Chemistry

JEE Main 2023 (January 25th Shift 1) Maths Question Paper with Answer Key

JEE Main 2023 (January 24th Shift 2) Chemistry Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Login 2045: Step-by-Step Instructions and Details

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

NCERT Solutions for Class 11 Chemistry Chapter 8 Organic Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 6 Equilibrium

NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons
