Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

The resultant of $\vec A$ and $\vec B$ is perpendicular to $\vec A$. What is the angle between $\vec A$ and $\vec B$?
A) ${\cos ^{ - 1}}\left( {\dfrac{A}{B}} \right)$
B) ${\cos ^{ - 1}}\left( { - \dfrac{A}{B}} \right)$
C) ${\sin ^{ - 1}}\left( {\dfrac{A}{B}} \right)$
D) ${\sin ^{ - 1}}\left( { - \dfrac{A}{B}} \right)$

seo-qna
Last updated date: 16th May 2024
Total views: 44.4k
Views today: 1.44k
Answer
VerifiedVerified
44.4k+ views
Hint: The resultant of two vectors is the vector addition of two vectors. Vectors can be added following two rules of addition: triangle law of addition or parallelogram law of addition. We can draw the vectors with co-initial points to illustrate the parallelogram law of vectors.

Formulae used:
The formula for the angle between resultant vector $\left( {\vec A + \vec B} \right)$ and a vector $\vec A$ is
$\tan \alpha = \dfrac{{b\sin \theta }}{{a + b\cos \theta }}$
Where $\alpha $ is the angle between resultant and the original vector and $\theta $ is the angle between the two vectors.

Complete step by step solution:

In the question it is given that the angle between resultant vector $\left( {\vec A + \vec B} \right)$ and a vector $\vec A$ is ${90^\circ }$ , that is, the resultant vector is perpendicular to the original vector.
$ \Rightarrow \alpha = {90^\circ }$
This means that
$\tan {90^\circ } = \dfrac{{B\sin \theta }}{{A + B\cos \theta }}$
As $\tan {90^\circ } \approx \infty $, for a fraction to approach infinity, the denominator of the fraction has to be zero
$A + B\cos \theta = 0$
$ \Rightarrow \cos \theta = - \dfrac{B}{A}$
$ \Rightarrow \cos \theta = - \dfrac{B}{A}$
$ \Rightarrow \theta = {\cos ^{ - 1}}( - \dfrac{B}{A})$

So the angle between the vectors is (B), ${\cos ^{ - 1}}\left( { - \dfrac{A}{B}} \right)$.

Additional information:
To derive the formula for the angle between the vectors we use the parallelogram law of vector addition. If $\vec A$ and $\vec B$ are vectors acting simultaneously from a point, representing both the magnitude and direction of the vectors, and $\theta $ is the angle between them then, then the diagonal of the parallelogram passing through the common vertices is the resultant. The angle between resultant and base is found by extending the base until a right angled triangle is formed and using Pythagoras and basic trigonometry to find the formula

Note: To solve such questions, we can also look at it from the point of view of triangle addition of vectors but that would make the formula more complicated. In parallelogram law of additions, both vectors and resultant share a common origin point, hence making the angle between the vectors more evident.