
Question: If \[U = \left[ {\begin{array}{*{20}{c}}2&{ - 3}&4\end{array}} \right]\], \[X = \left[ {\begin{array}{*{20}{c}}0&2&3\end{array}} \right]\], \[V = \left[ {\begin{array}{*{20}{c}}3\\2\\1\end{array}} \right]\]and\[Y = \left[ {\begin{array}{*{20}{c}}2\\2\\4\end{array}} \right]\], then what is the value of \[UV + XY\]?
A.\[\left[ {20} \right]\]
B.20
C. \[\left[ { - 20} \right]\]
D. -20
Answer
216k+ views
Hint: To solve the question we will first perform the multiplication operation on the matrices, and then perform the addition operation on the result we got from multiplying the matrices, then we will get the required result.
Formula Used:
We will use the multiplication of matrices with different dimensions, i.e.,
\[\left[ {\begin{array}{*{20}{c}}a&b&c\end{array}} \right]\left[ {\begin{array}{*{20}{c}}x\\y\\z\end{array}} \right] = \left[ {a \times x + b \times y + c \times z} \right]\]
Complete step by step solution:
Given matrices are \[U = \left[ {\begin{array}{*{20}{c}}2&{ - 3}&4\end{array}} \right]\], \[X = \left[ {\begin{array}{*{20}{c}}0&2&3\end{array}} \right]\], \[V = \left[ {\begin{array}{*{20}{c}}3\\2\\1\end{array}} \right]\]and\[Y = \left[ {\begin{array}{*{20}{c}}2\\2\\4\end{array}} \right]\]
Now we will multiply the matrices and then perform the addition operation on the matrices, we will get,
\[ \Rightarrow UV + XY = \left[ {\begin{array}{*{20}{c}}2&{ - 3}&4\end{array}} \right]\left[ {\begin{array}{*{20}{c}}3\\2\\1\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}0&2&3\end{array}} \right]\left[ {\begin{array}{*{20}{c}}2\\2\\4\end{array}} \right]\]
Now we will perform the multiplication operation first, we will get,
\[ \Rightarrow UV + XY = \left[ {2 \times 3 + \left( { - 3 \times 2} \right) + 4 \times 1} \right] + \left[ {0 \times 2 + 2 \times 2 + 3 \times 4} \right]\],
Now we will simplify by multiplying the terms, we will get,
\[ \Rightarrow UV + XY = \left[ {6 - 6 + 4} \right] + \left[ {0 + 4 + 12} \right]\]
Now we will further simplify by adding, then we will get,
\[ \Rightarrow UV + XY = \left[ 4 \right] + \left[ {16} \right]\]
Now we will perform the addition operation of the matrices, we will get,
\[ \Rightarrow UV + XY = \left[ {16 + 4} \right]\]
Now we will further simplify by adding, then we will get,
\[ \Rightarrow UV + XY = \left[ {20} \right]\]
The correct option is A.
Note: We know that to add two matrices, the dimensions of the two matrices should be same otherwise we cannot add the matrices. But in case of multiplication i.e., if we want to multiply any of the two matrices, the two matrices should have same inner dimensions, then the resulted matrix dimensions will be of the outer dimensions as its final dimension. It is important to know that the scalar multiplication of the matrix will not have any impact, as the original dimensions will be same as the resulted matrix. In other words the resulted matrix dimensions will be same as the original matrix dimension.
Formula Used:
We will use the multiplication of matrices with different dimensions, i.e.,
\[\left[ {\begin{array}{*{20}{c}}a&b&c\end{array}} \right]\left[ {\begin{array}{*{20}{c}}x\\y\\z\end{array}} \right] = \left[ {a \times x + b \times y + c \times z} \right]\]
Complete step by step solution:
Given matrices are \[U = \left[ {\begin{array}{*{20}{c}}2&{ - 3}&4\end{array}} \right]\], \[X = \left[ {\begin{array}{*{20}{c}}0&2&3\end{array}} \right]\], \[V = \left[ {\begin{array}{*{20}{c}}3\\2\\1\end{array}} \right]\]and\[Y = \left[ {\begin{array}{*{20}{c}}2\\2\\4\end{array}} \right]\]
Now we will multiply the matrices and then perform the addition operation on the matrices, we will get,
\[ \Rightarrow UV + XY = \left[ {\begin{array}{*{20}{c}}2&{ - 3}&4\end{array}} \right]\left[ {\begin{array}{*{20}{c}}3\\2\\1\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}0&2&3\end{array}} \right]\left[ {\begin{array}{*{20}{c}}2\\2\\4\end{array}} \right]\]
Now we will perform the multiplication operation first, we will get,
\[ \Rightarrow UV + XY = \left[ {2 \times 3 + \left( { - 3 \times 2} \right) + 4 \times 1} \right] + \left[ {0 \times 2 + 2 \times 2 + 3 \times 4} \right]\],
Now we will simplify by multiplying the terms, we will get,
\[ \Rightarrow UV + XY = \left[ {6 - 6 + 4} \right] + \left[ {0 + 4 + 12} \right]\]
Now we will further simplify by adding, then we will get,
\[ \Rightarrow UV + XY = \left[ 4 \right] + \left[ {16} \right]\]
Now we will perform the addition operation of the matrices, we will get,
\[ \Rightarrow UV + XY = \left[ {16 + 4} \right]\]
Now we will further simplify by adding, then we will get,
\[ \Rightarrow UV + XY = \left[ {20} \right]\]
The correct option is A.
Note: We know that to add two matrices, the dimensions of the two matrices should be same otherwise we cannot add the matrices. But in case of multiplication i.e., if we want to multiply any of the two matrices, the two matrices should have same inner dimensions, then the resulted matrix dimensions will be of the outer dimensions as its final dimension. It is important to know that the scalar multiplication of the matrix will not have any impact, as the original dimensions will be same as the resulted matrix. In other words the resulted matrix dimensions will be same as the original matrix dimension.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Average and RMS Value in Electrical Circuits

