
Nitrobenzene on further excessive nitration gives
A. Sym-trinitrobenzne
B. M-Dinitrobenzne
C. P-Dinitrobenzene
D. All of these
Answer
163.5k+ views
Hint: Nitration is a chemical process by which nitro group (s) are introduced to a chemical compound. Nitration can be done by reacting benzene with \[{\rm{HN}}{{\rm{O}}_{\rm{3}}}\] (nitric acid ) in presence of sulphuric acid (\[{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\]).
Complete Step by Step Solution:
Let's discuss nitrobenzene first. Nitrobenzene is a chemical species possessing the chemical formula of\[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{O}}_{\rm{2}}}\] . It shows the insolubility in water. It is A pale yellow coloured oil possessing the odour of almond. Freezing of it gives green-yellow coloured crystals. It is manufactured in huge quantities from benzene. The structure of nitrobenzene is,

Image: Nitrobenzene
Here, we have to find out the product which is produced when excessive nitration of nitrobenzene occurs.
Here, nitrobenzene undergoes excessive nitration. When nitrobenzene undergoes a reaction with nitric acid in presence of sulphuric acid, the following reaction occurs.
\[{\rm{HN}}{{\rm{O}}_{\rm{3}}} + {{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} \to {\rm{N}}{{\rm{O}}_{\rm{2}}}^ + + {{\rm{H}}_{\rm{2}}}{\rm{O}} + {\rm{HS}}{{\rm{O}}_{\rm{4}}}^ - \]
Although \[{\rm{HN}}{{\rm{O}}_{\rm{3}}}\] is an acid, in the above reaction, it acts as a base and \[{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\] acts as an acid. And we know, nitro group is an meta directing and deactivating group. Therefore, the product obtained is,

Image: Nitration of nitrobenzene
Further nitration of nitration is not possible because of the deactivating nitro group.
Hence, the option B is right.
Note: Nitration of benzene takes place in three steps, First step is, Activation of the electrophile by the acid. Second step is an attack of the activated electrophile by benzene and the last step is deprotonation to restore the aromatic ring and regeneration of the acidic catalyst.
Complete Step by Step Solution:
Let's discuss nitrobenzene first. Nitrobenzene is a chemical species possessing the chemical formula of\[{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{N}}{{\rm{O}}_{\rm{2}}}\] . It shows the insolubility in water. It is A pale yellow coloured oil possessing the odour of almond. Freezing of it gives green-yellow coloured crystals. It is manufactured in huge quantities from benzene. The structure of nitrobenzene is,

Image: Nitrobenzene
Here, we have to find out the product which is produced when excessive nitration of nitrobenzene occurs.
Here, nitrobenzene undergoes excessive nitration. When nitrobenzene undergoes a reaction with nitric acid in presence of sulphuric acid, the following reaction occurs.
\[{\rm{HN}}{{\rm{O}}_{\rm{3}}} + {{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} \to {\rm{N}}{{\rm{O}}_{\rm{2}}}^ + + {{\rm{H}}_{\rm{2}}}{\rm{O}} + {\rm{HS}}{{\rm{O}}_{\rm{4}}}^ - \]
Although \[{\rm{HN}}{{\rm{O}}_{\rm{3}}}\] is an acid, in the above reaction, it acts as a base and \[{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\] acts as an acid. And we know, nitro group is an meta directing and deactivating group. Therefore, the product obtained is,

Image: Nitration of nitrobenzene
Further nitration of nitration is not possible because of the deactivating nitro group.
Hence, the option B is right.
Note: Nitration of benzene takes place in three steps, First step is, Activation of the electrophile by the acid. Second step is an attack of the activated electrophile by benzene and the last step is deprotonation to restore the aromatic ring and regeneration of the acidic catalyst.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
