
When methyl iodide is heated with ammonia, what is the product obtained?
(A) Methylamine
(B) Dimethylamine
(C) Trimethylamine
(D) A mixture of the above three amines
Answer
225k+ views
Hint: In this question it is said that when methyl iodide is reacted or we can also say heated with ammonia then what is the product is going to be obtained from both of the reactants. Whereas, we know that we both have reacted and a mixture is obtained and we have to classify this product in the solution.
Complete Step by Step Solution:
As for doing the solution of this question we have to write the whole reaction of the given reactants:
$C{H_3}I\xrightarrow[\Delta ]{{N{H_3}}}C{H_3}N{H_2}$
As per completing the first part of the reaction we get Methyl amine as a result.
For the whole process to be done we react Methyl amine in presence of Methyl iodide to get the solution:
$C{H_3}N{H_2}\xrightarrow{{C{H_3}I}}{(C{H_3})_2}NH$
As by performing this reaction we get Di methyl amine.
By making reaction of Dimethyl amine with Methyl iodide we get,
${(C{H_3})_2}NH\xrightarrow{{C{H_3}I}}{(C{H_3})_3}N$
As by doing this reaction we get, Tri methyl amine as in the product.
By performing full reaction in process we can see clarity of the reaction,
$C{H_3}I\xrightarrow[\Delta ]{{N{H_3}}}C{H_3}N{H_2}\xrightarrow{{C{H_3}I}}{(C{H_3})_2}NH\xrightarrow{{C{H_3}I}}{(C{H_3})_3}N$.
As a result from writing the whole process of the reaction we get that, when Methyl iodide is heated with ammonia we get, Methylamine, Dimethylamine and trimethylamine all the three are formed in this reaction.
Therefore, the correct answer is a mixture of all three amines.
Hence, the correct option is (D).
Note: We read this full topic in the preparation of amines whereas, there is many types of methods by which we can prepare amines. As we know that amine is a organic compound which having a nitrogen atom with a lone pair basically in all the methods of preparation amine is derived using ammonia at most specific times.
Complete Step by Step Solution:
As for doing the solution of this question we have to write the whole reaction of the given reactants:
$C{H_3}I\xrightarrow[\Delta ]{{N{H_3}}}C{H_3}N{H_2}$
As per completing the first part of the reaction we get Methyl amine as a result.
For the whole process to be done we react Methyl amine in presence of Methyl iodide to get the solution:
$C{H_3}N{H_2}\xrightarrow{{C{H_3}I}}{(C{H_3})_2}NH$
As by performing this reaction we get Di methyl amine.
By making reaction of Dimethyl amine with Methyl iodide we get,
${(C{H_3})_2}NH\xrightarrow{{C{H_3}I}}{(C{H_3})_3}N$
As by doing this reaction we get, Tri methyl amine as in the product.
By performing full reaction in process we can see clarity of the reaction,
$C{H_3}I\xrightarrow[\Delta ]{{N{H_3}}}C{H_3}N{H_2}\xrightarrow{{C{H_3}I}}{(C{H_3})_2}NH\xrightarrow{{C{H_3}I}}{(C{H_3})_3}N$.
As a result from writing the whole process of the reaction we get that, when Methyl iodide is heated with ammonia we get, Methylamine, Dimethylamine and trimethylamine all the three are formed in this reaction.
Therefore, the correct answer is a mixture of all three amines.
Hence, the correct option is (D).
Note: We read this full topic in the preparation of amines whereas, there is many types of methods by which we can prepare amines. As we know that amine is a organic compound which having a nitrogen atom with a lone pair basically in all the methods of preparation amine is derived using ammonia at most specific times.
Recently Updated Pages
JEE Main 2025-26 Mock Test: Organic Compounds Containing Nitrogen

JEE Main 2025-26 Organic Compounds Containing Nitrogen Mock Test

JEE Main Chemical Kinetics Mock Test 2025-26: Free Practice Online

JEE Main 2025-26 Organic Compounds Containing Oxygen Mock Test

JEE Main 2025-26 Organic Compounds Containing Halogens Mock Test

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Hybridisation in Chemistry – Concept, Types & Applications

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 4 The D and F Block Elements

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

