
How long (in hours) must a current of 5 ampere be maintained to electroplate 60g of calcium from molten \[\text{CaC}{{\text{l}}_{\text{2}}}\] ?
A.27 hours
B.8.3 hours
C. 11 hours
D. 16 hours
Answer
222.6k+ views
Hint: The question here talks about the time required for decomposition,so, by calculating the the charge (Q) ,we will be able to substitute in the given formula ,and find the time taken.Our main emphasis must be on calculating the total number of moles required by the compound.
Complete solution step by step:
By the concept of electrochemistry, and following the faraday’s law,the formula for charge Q passed is given by:
Q=It
Where I= is the current in ampere
T= is the time in seconds required to be deposited
Let’s see the reaction of calcium:
${ Ca }\xrightarrow { Ca }^{ 2+ } + { 2e }^{ - }\\$ (oxidation)
${ Cl }_{ 2 } +{ 2e }^{ -}\xrightarrow { 2Cl }^{ - }\\$ (reduction)
$ Ca +{ Cl }_{ 2 }+ { 2e }^{ - }\xrightarrow { Ca }^{ 2+ }+ 2{ e }^{ - }+ { 2Cl }^{ - }$ (net redox reaction)
Therefore the number of moles=2
Now,the molar mass of calcium= 40g/mol
So, for calculating the number of moles we have the formula as :${ given weight }/{ molecular weight }$
Then number of moles for 60 grams of calcium will be=${ 60 }/{ 40 }$ = 1.5
Now we know that 1 mole of electron requires 96500 C
So, 2 moles of electron will require = 193000 C
Therefore, 1.5 moles will require : $1\cdot 5\times 193000$
=289500 C
Now,in order to find the time, t= ${ Q }/{ I }$
${ 289500 }/{ 5 }$= 57900 s
In order to convert it in hours,we will divide by 3600,which gives us : 16 hours
So the correct option is D.
Note: In order to find the number of electrons, we must always try to write the full oxidation and reduction reaction.So,it is always important to find the total number of loss and gain in electrons,so that we could balance the redox reaction.
Complete solution step by step:
By the concept of electrochemistry, and following the faraday’s law,the formula for charge Q passed is given by:
Q=It
Where I= is the current in ampere
T= is the time in seconds required to be deposited
Let’s see the reaction of calcium:
${ Ca }\xrightarrow { Ca }^{ 2+ } + { 2e }^{ - }\\$ (oxidation)
${ Cl }_{ 2 } +{ 2e }^{ -}\xrightarrow { 2Cl }^{ - }\\$ (reduction)
$ Ca +{ Cl }_{ 2 }+ { 2e }^{ - }\xrightarrow { Ca }^{ 2+ }+ 2{ e }^{ - }+ { 2Cl }^{ - }$ (net redox reaction)
Therefore the number of moles=2
Now,the molar mass of calcium= 40g/mol
So, for calculating the number of moles we have the formula as :${ given weight }/{ molecular weight }$
Then number of moles for 60 grams of calcium will be=${ 60 }/{ 40 }$ = 1.5
Now we know that 1 mole of electron requires 96500 C
So, 2 moles of electron will require = 193000 C
Therefore, 1.5 moles will require : $1\cdot 5\times 193000$
=289500 C
Now,in order to find the time, t= ${ Q }/{ I }$
${ 289500 }/{ 5 }$= 57900 s
In order to convert it in hours,we will divide by 3600,which gives us : 16 hours
So the correct option is D.
Note: In order to find the number of electrons, we must always try to write the full oxidation and reduction reaction.So,it is always important to find the total number of loss and gain in electrons,so that we could balance the redox reaction.
Recently Updated Pages
JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

The D and F Block Elements Class 12 Chemistry Chapter 4 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter Chapter 7 Alcohol Phenol and Ether

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 8 Aldehydes Ketones And Carboxylic Acids

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

