
What is \[\left[ {\begin{array}{*{20}{c}}
1 \\
{ - 1} \\
2
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1}
\end{array}} \right] = \]
A. \[\left[ { - 1} \right]\]
B. \[\left[ {\begin{array}{*{20}{c}}
2 \\
{ - 1} \\
{ - 2}
\end{array}} \right]\]
C. \[\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1} \\
{ - 2}&{ - 1}&1 \\
4&2&{ - 2}
\end{array}} \right]\]
D. Not defined
Answer
232.8k+ views
Hint: In the given problem we first check out the columns and rows of the given matrices. The number of columns of the first matrix must be equal to the number of rows of the second matrix in order to multiply the two given matrices.
Formula Used:
If \[A = {[{a_{ij}}]_{m \times n}}\] and \[B = {[{b_{ij}}]_{n \times p}}\] then we can say that \[A \times B = C\] where the value of C is
\[C = {[{c_{ij}}]_{m \times p}}\]
Here \[{c_{ij}} = \mathop \sum \limits_{j = 1}^m {a_{ij}}{b_{jk}} = {a_{i1}}{b_{1k}} + {a_{i2}}{b_{2k}} + ........ + {a_{im}}{b_{mk}}\]
Complete step by step Solution:
We are given two matrices \[{\left[ {\begin{array}{*{20}{c}}
1 \\
{ - 1} \\
2
\end{array}} \right]_{3 \times 1}}\]and \[{\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1}
\end{array}} \right]_{1 \times 3}}\]
There are three rows and one column in the first matrix and in the second matrix there is one column row and three columns.
So, after multiplication we will get a matrix in which we have three rows and three columns.
\[
\left[ {\begin{array}{*{20}{c}}
1 \\
{ - 1} \\
2
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1}
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
{2 \times 1}&{1 \times 1}&{1 \times - 1} \\
{ - 1 \times 2}&{ - 1 \times 1}&{ - 1 \times - 1} \\
{2 \times 2}&{2 \times 1}&{2 \times - 1}
\end{array}} \right] \\
\\
\]
\[ = \left[ {\begin{array}{*{20}{c}}
2&1&{ - 1} \\
{ - 2}&{ - 1}&1 \\
4&2&{ - 2}
\end{array}} \right]\]
Therefore, the correct option is (C).
Note: To solve the given problem, one must know to multiply two matrices. Before multiplying two matrices it is important to check whether the number of columns of the first matrix and number of rows of the second matrix are equal.
Formula Used:
If \[A = {[{a_{ij}}]_{m \times n}}\] and \[B = {[{b_{ij}}]_{n \times p}}\] then we can say that \[A \times B = C\] where the value of C is
\[C = {[{c_{ij}}]_{m \times p}}\]
Here \[{c_{ij}} = \mathop \sum \limits_{j = 1}^m {a_{ij}}{b_{jk}} = {a_{i1}}{b_{1k}} + {a_{i2}}{b_{2k}} + ........ + {a_{im}}{b_{mk}}\]
Complete step by step Solution:
We are given two matrices \[{\left[ {\begin{array}{*{20}{c}}
1 \\
{ - 1} \\
2
\end{array}} \right]_{3 \times 1}}\]and \[{\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1}
\end{array}} \right]_{1 \times 3}}\]
There are three rows and one column in the first matrix and in the second matrix there is one column row and three columns.
So, after multiplication we will get a matrix in which we have three rows and three columns.
\[
\left[ {\begin{array}{*{20}{c}}
1 \\
{ - 1} \\
2
\end{array}} \right]\left[ {\begin{array}{*{20}{c}}
2&1&{ - 1}
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
{2 \times 1}&{1 \times 1}&{1 \times - 1} \\
{ - 1 \times 2}&{ - 1 \times 1}&{ - 1 \times - 1} \\
{2 \times 2}&{2 \times 1}&{2 \times - 1}
\end{array}} \right] \\
\\
\]
\[ = \left[ {\begin{array}{*{20}{c}}
2&1&{ - 1} \\
{ - 2}&{ - 1}&1 \\
4&2&{ - 2}
\end{array}} \right]\]
Therefore, the correct option is (C).
Note: To solve the given problem, one must know to multiply two matrices. Before multiplying two matrices it is important to check whether the number of columns of the first matrix and number of rows of the second matrix are equal.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

Understanding How a Current Loop Acts as a Magnetic Dipole

