In Zeisel’s method for the determination of methoxy groups, a sample of 2.68gm of a compound (A) gave 14.08gm of $AgI$. If the molecular weight of compound (A) is 134, the number of $\left( { - OC{H_3}} \right)$ group(s) in the compound (A) is-
(A) 1
(B) 2
(C) 3
(D) 4
Answer
271.8k+ views
Hint: We will first understand what is meant by Zeisel’s method. Then we will undergo the reaction which the compound goes through while using this method. We will then simply find out the resultant weight of the $AgI$ precipitate formed.
Complete step by step answer:
As we know that the Zeisel’s method is used to count the number of methoxy groups in that compound. We use the agents that will only react with the methoxy groups in that compound to count its number.
In Zeisel’s method, we simply heat the given compound with hydriodic acid which in turn results in iodoalkanes. After doing so, we pass this iodoalkane through an ethanolic solution in the presence of silver nitrite $\left( {AgN{O_3}} \right)$. This results in a precipitate of $AgI$. We measure the weight of this $AgI$ precipitate which gives us the number of methoxy groups present. In other words, the number of moles of $AgI$ will be equal to the number of $\left( { - OC{H_3}} \right)$ groups.
Now, in the question, 2.68gm of compound A is given. This compound A gives us 14.08 gm of $AgI$.
Now we will calculate the number of methoxy groups in one mole.
Now, we already know that 2.68gm of A $ \to $ 14.08gm of $AgI$
So, 134gm of A $ \to $ $\dfrac{{14.08}}{{2.68}} \times 134$
$ \Rightarrow 704gm$ of $AgI$ precipitate
Thus, the number of molecules in $AgI$-
Molecular weight of $AgI$ is 235.
$
\Rightarrow \dfrac{{704}}{{235}} \\
\\
\Rightarrow 3moles \\
$
This means that the number of methoxy groups are 3.
Hence, it is clear that option C is the correct option.
Note: Methanol and dimethyl ether are the simplest methoxy compounds. Anisole and vanillin are other methoxy ethers. Most alkoxides contain methoxy groups, e.g. orthosilicate tetramethyl and methoxide titanium. These compounds frequently are known as methoxides.
Complete step by step answer:
As we know that the Zeisel’s method is used to count the number of methoxy groups in that compound. We use the agents that will only react with the methoxy groups in that compound to count its number.
In Zeisel’s method, we simply heat the given compound with hydriodic acid which in turn results in iodoalkanes. After doing so, we pass this iodoalkane through an ethanolic solution in the presence of silver nitrite $\left( {AgN{O_3}} \right)$. This results in a precipitate of $AgI$. We measure the weight of this $AgI$ precipitate which gives us the number of methoxy groups present. In other words, the number of moles of $AgI$ will be equal to the number of $\left( { - OC{H_3}} \right)$ groups.
Now, in the question, 2.68gm of compound A is given. This compound A gives us 14.08 gm of $AgI$.
Now we will calculate the number of methoxy groups in one mole.
Now, we already know that 2.68gm of A $ \to $ 14.08gm of $AgI$
So, 134gm of A $ \to $ $\dfrac{{14.08}}{{2.68}} \times 134$
$ \Rightarrow 704gm$ of $AgI$ precipitate
Thus, the number of molecules in $AgI$-
Molecular weight of $AgI$ is 235.
$
\Rightarrow \dfrac{{704}}{{235}} \\
\\
\Rightarrow 3moles \\
$
This means that the number of methoxy groups are 3.
Hence, it is clear that option C is the correct option.
Note: Methanol and dimethyl ether are the simplest methoxy compounds. Anisole and vanillin are other methoxy ethers. Most alkoxides contain methoxy groups, e.g. orthosilicate tetramethyl and methoxide titanium. These compounds frequently are known as methoxides.
Recently Updated Pages
JoSAA Counselling 2026: JoSAA 2026 Mock Seat Allotment LIVE: Round 2 Result Released, Registration, Choice Filling and Ranks

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

Understanding the Different Types of Solutions in Chemistry

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Class 12 Chemistry Question Paper 2026 PDF Download (All Sets) with Answer Key

NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2025-26

