In the figure shown the wave speed is ‘\[v\]’. The velocity of the car is ‘\[{v_0}\]’. The beat frequency for the observer will be:
A. \[\dfrac{{2{f_0}v{v_0}}}{{{v^2} + v_0^2}} \\ \]
B. \[\dfrac{{2{f_0}{v^2}}}{{{v^2} - v_0^2}} \\ \]
C. \[\dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}} \\ \]
D. \[\dfrac{{{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Answer
Verified
117.9k+ views
Hint: If the frequency when the car is approaching is \[{f_1}\] and when the car is leaving is \[{f_2}\]. Get the value of \[{f_1}\] and \[{f_2}\] in terms of \[{f_0}\] . The Doppler effect or Doppler shift can be describing the changes in frequency of sound or light wave produced by a moving source with respect to an observer. Also, we know that the beat frequency is defined as the difference in frequency of two waves. By using this we can get the result.
Formula used:
Frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right)\]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right)\]
Where \[{f_1}\] and \[{f_2}\] is the frequency required, \[{f_0}\] is the given frequency, \[v\] is the velocity of the observer and \[{v_0}\] is the velocity of sound.
Beat frequency is given as,
\[{f_1} - {f_2}\]
Where \[{f_1} - {f_2}\] represents the change in frequency.
Complete step by step solution:
As we know that the frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right) \\ \]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right) \\ \]
Now the beat frequency = \[{f_1} - {f_2} \\ \]
\[\text{beat frequency} = {f_0}v\left( {\dfrac{1}{{v - {v_0}}} - \dfrac{1}{{v + {v_0}}}} \right) \\ \]
\[\Rightarrow \text{beat frequency} = {f_0}v\left( {\dfrac{{v + {v_0} - v + {v_0}}}{{{v^2} - v_0^2}}} \right) \\ \]
\[\therefore \text{beat frequency} = \dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Hence option C is the correct answer.
Note:The formula for Doppler Effect is related to the frequency of the sound of an object with its velocity. Doppler Effect is defined as the change in wave frequency during the relative motion between the wave source and its observer. It was given by Christian Johann Doppler. Beats can be determined by subtracting the initial frequency with the frequency observed by the observer.
Formula used:
Frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right)\]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right)\]
Where \[{f_1}\] and \[{f_2}\] is the frequency required, \[{f_0}\] is the given frequency, \[v\] is the velocity of the observer and \[{v_0}\] is the velocity of sound.
Beat frequency is given as,
\[{f_1} - {f_2}\]
Where \[{f_1} - {f_2}\] represents the change in frequency.
Complete step by step solution:
As we know that the frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right) \\ \]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right) \\ \]
Now the beat frequency = \[{f_1} - {f_2} \\ \]
\[\text{beat frequency} = {f_0}v\left( {\dfrac{1}{{v - {v_0}}} - \dfrac{1}{{v + {v_0}}}} \right) \\ \]
\[\Rightarrow \text{beat frequency} = {f_0}v\left( {\dfrac{{v + {v_0} - v + {v_0}}}{{{v^2} - v_0^2}}} \right) \\ \]
\[\therefore \text{beat frequency} = \dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Hence option C is the correct answer.
Note:The formula for Doppler Effect is related to the frequency of the sound of an object with its velocity. Doppler Effect is defined as the change in wave frequency during the relative motion between the wave source and its observer. It was given by Christian Johann Doppler. Beats can be determined by subtracting the initial frequency with the frequency observed by the observer.
Recently Updated Pages
JEE Main 2025: Application Form, Exam Dates, Eligibility, and More
Uniform Acceleration - Definition, Equation, Examples, and FAQs
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Trending doubts
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
Physics Average Value and RMS Value JEE Main 2025
Inductive Effect and Acidic Strength - Types, Relation and Applications for JEE
Free Radical Substitution Mechanism of Alkanes for JEE Main 2025
Other Pages
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 8 Mechanical Properties of Solids
NCERT Solutions for Class 11 Physics Chapter 4 Laws of Motion
Thermodynamics Class 11 Notes CBSE Physics Chapter 11 (Free PDF Download)
NCERT Solutions for Class 11 Physics Chapter 5 Work Energy and Power
NCERT Solutions for Class 11 Physics Chapter 3 Motion In A Plane