
In Carius’ method of estimation of halogen, 0.172 g of an organic compound showed the presence of 0.08 g of bromine. Which of these is the correct structure of the compound?
A.

B.

C.

D.

Answer
154.8k+ views
Hint: Carius method is a procedure used to estimate the percentage of halogen in an organic compound.
In this method, a halogen-containing organic compound is heated in the presence of silver nitrate.
Formula Used:
Percentage of halogen =
.×100
Complete Step by Step Solution:
The mass of the organic compound = 0.172g
Mass of bromine present in the organic compound = 0.08g
So, the percentage of bromine = .
The atomic mass of bromine = 80g.
A.

Image: Option A
This is bromomethane.
Molar mass
The molar mass of bromoethane is 95g.
There is one bromine atom.
So, it contains 80g of bromine.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
B.

Image: Option B
This is 2,4-dibromoaniline ( )
Molar mass
It contains 2 bromine atoms.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
C.

Image: Option C
This is 4-bromoaniline( ).
Molar mass
It contains one bromine atom.
Percentage of bromine
This is the same percentage as the bromine in the given organic compound.
D.

Image: Option D
This is bromoethane ( ).
Molar mass
Only one bromine atom is present.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
So, option C is correct.
Additional Information:In the Carius method, a known mass of an organic compound is heated with fuming nitric acid in the presence of silver nitrate contained in a hard glass tube known as the Carius tube. Carbon and hydrogen that are present in the compound are oxidised to carbon dioxide and water.
The halogen present forms the corresponding silver halide.
It is filtered, washed, dried and weighed.
Note: While attending to the question, one must calculate the percentage of bromine present in each given option. He/she should have calculated the percentage of bromine in the given organic compound first. Then, after matching the bromine percentage in the given organic compound with the bromine percentage of individual options, the correct organic compound will be determined.
In this method, a halogen-containing organic compound is heated in the presence of silver nitrate.
Formula Used:
Percentage of halogen =
Complete Step by Step Solution:
The mass of the organic compound = 0.172g
Mass of bromine present in the organic compound = 0.08g
So, the percentage of bromine =
The atomic mass of bromine = 80g.
A.

Image: Option A
This is bromomethane.
Molar mass
The molar mass of bromoethane is 95g.
There is one bromine atom.
So, it contains 80g of bromine.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
B.

Image: Option B
This is 2,4-dibromoaniline (
Molar mass
It contains 2 bromine atoms.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
C.

Image: Option C
This is 4-bromoaniline(
Molar mass
It contains one bromine atom.
Percentage of bromine
This is the same percentage as the bromine in the given organic compound.
D.

Image: Option D
This is bromoethane (
Molar mass
Only one bromine atom is present.
So, the percentage of bromine
This doesn't resemble the percentage of bromine in the given organic compound.
So, option C is correct.
Additional Information:In the Carius method, a known mass of an organic compound is heated with fuming nitric acid in the presence of silver nitrate contained in a hard glass tube known as the Carius tube. Carbon and hydrogen that are present in the compound are oxidised to carbon dioxide and water.
The halogen present forms the corresponding silver halide.
It is filtered, washed, dried and weighed.
Note: While attending to the question, one must calculate the percentage of bromine present in each given option. He/she should have calculated the percentage of bromine in the given organic compound first. Then, after matching the bromine percentage in the given organic compound with the bromine percentage of individual options, the correct organic compound will be determined.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

The stability of the following alkali metal chlorides class 11 chemistry JEE_Main

Displacement-Time Graph and Velocity-Time Graph for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

JEE Advanced 2025 Notes

Electrical Field of Charged Spherical Shell - JEE
