
In any triangle $ABC$, the value of $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$ is
A. $3ab{{c}^{2}}$
B. $3{{a}^{2}}bc$
C. $3abc$
D. $3a{{b}^{2}}c$
Answer
233.1k+ views
Hint: To solve this question, we will use all the three projection formulas. We will first simplify the given equation and rewrite it. We will then apply the projection formulas and determine the value of the equation.
Projection formula can be defined as the length of any side of a triangle is equal to the sum of the projections of two other sides on it.
Formula Used: There are three projection formulas:
\[\begin{align}
& a=c\cos B+b\cos C \\
& b=c\cos A+a\cos C \\
& c=b\cos A+a\cos B \\
\end{align}\]
Complete step by step solution: We are given a triangle $ABC$ and we have to determine the value of $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$.
We will simplify the equation $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$ and derive its value.
$\begin{align}
& =(a{{b}^{2}}+a{{c}^{2}})\cos A+(b{{c}^{2}}+b{{a}^{2}})\cos B+(c{{a}^{2}}+c{{b}^{2}})\cos C \\
& =a{{b}^{2}}\cos A+a{{c}^{2}}\cos A+b{{c}^{2}}\cos B+b{{a}^{2}}\cos B+c{{a}^{2}}\cos C+c{{b}^{2}}\cos C \\
\end{align}$
We will now rewrite the equation.
$\begin{align}
& =a{{b}^{2}}\cos A+b{{a}^{2}}\cos B+a{{c}^{2}}\cos A+c{{a}^{2}}\cos C+b{{c}^{2}}\cos B+c{{b}^{2}}\cos C \\
& =ab(b\cos A+a\cos B)+ac(c\cos A+a\cos C)+bc(c\cos B+b\cos C) \\
\end{align}$
We will now substitute the projection formula in the above equation.
$\begin{align}
& =abc+abc+abc \\
& =3abc \\
\end{align}$
The value of $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$ for the triangle $ABC$ is $3abc$. Hence the correct option is (C).
Note: There are three types of a triangle in terms of angle. It can be either acute, obtuse or right angled triangle. In terms of the shape there are also three kind of triangle scalene, isosceles and equilateral triangle. Some properties of triangles apply equally on every triangle however some properties are specific to a type of triangle.
For example- To calculate an area of a triangle the Heron’s formula applies on every triangle but the area of the right angled triangle is specific to it only. The angle sum property applies on every triangle irrespective of their type on the basis of angle or shape.
Hence we should once check before using any properties of a triangle that if it is applicable or not.
Projection formula can be defined as the length of any side of a triangle is equal to the sum of the projections of two other sides on it.
Formula Used: There are three projection formulas:
\[\begin{align}
& a=c\cos B+b\cos C \\
& b=c\cos A+a\cos C \\
& c=b\cos A+a\cos B \\
\end{align}\]
Complete step by step solution: We are given a triangle $ABC$ and we have to determine the value of $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$.
We will simplify the equation $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$ and derive its value.
$\begin{align}
& =(a{{b}^{2}}+a{{c}^{2}})\cos A+(b{{c}^{2}}+b{{a}^{2}})\cos B+(c{{a}^{2}}+c{{b}^{2}})\cos C \\
& =a{{b}^{2}}\cos A+a{{c}^{2}}\cos A+b{{c}^{2}}\cos B+b{{a}^{2}}\cos B+c{{a}^{2}}\cos C+c{{b}^{2}}\cos C \\
\end{align}$
We will now rewrite the equation.
$\begin{align}
& =a{{b}^{2}}\cos A+b{{a}^{2}}\cos B+a{{c}^{2}}\cos A+c{{a}^{2}}\cos C+b{{c}^{2}}\cos B+c{{b}^{2}}\cos C \\
& =ab(b\cos A+a\cos B)+ac(c\cos A+a\cos C)+bc(c\cos B+b\cos C) \\
\end{align}$
We will now substitute the projection formula in the above equation.
$\begin{align}
& =abc+abc+abc \\
& =3abc \\
\end{align}$
The value of $a({{b}^{2}}+{{c}^{2}})\cos A+b({{c}^{2}}+{{a}^{2}})\cos B+c({{a}^{2}}+{{b}^{2}})\cos C$ for the triangle $ABC$ is $3abc$. Hence the correct option is (C).
Note: There are three types of a triangle in terms of angle. It can be either acute, obtuse or right angled triangle. In terms of the shape there are also three kind of triangle scalene, isosceles and equilateral triangle. Some properties of triangles apply equally on every triangle however some properties are specific to a type of triangle.
For example- To calculate an area of a triangle the Heron’s formula applies on every triangle but the area of the right angled triangle is specific to it only. The angle sum property applies on every triangle irrespective of their type on the basis of angle or shape.
Hence we should once check before using any properties of a triangle that if it is applicable or not.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 11 Maths Chapter 12 Limits and Derivatives (2025-26)

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

