
In a solution of 7.8gm benzene ${C_6}{H_6}$and 46.0 gm toluene (${C_6}{H_5}C{H_3}$), the mole fraction of benzene in this solution is :
a.) $\dfrac{1}{6}$
b.) $\dfrac{1}{5}$
c.) $\dfrac{1}{2}$
d.) $\dfrac{1}{3}$
Answer
136.2k+ views
Hint: The benzene has molecular mass of 78 g and the toluene has molecular mass of 92 g. From the given mass, the number of moles can be found out and from this, the mole fraction can be calculated by formula as -
$Mole fraction =$ $\dfrac{{Number{\text{ of moles of component}}}}{{Total{\text{ number of moles of all components}}}}$
Complete step by step solution:
First, let us write what is given to us in the question what we need to find out.
Mass of benzene (${C_6}{H_6}$) = 7.8 gm
Mass of toluene (${C_6}{H_5}C{H_3}$) = 46.0 gm
To find : mole fraction of benzene in this solution
Let us first see what is mole fraction.
Mole fraction may be defined as the number of moles of one component divided by the total number of moles of all the components in a solution. It is used to describe the concentration of a species.
Thus, we can write the formulas as -
Mole fraction = $\dfrac{{Number{\text{ of moles of component}}}}{{Total{\text{ number of moles of all components}}}}$
We are given mass of the components. First, we will find its number of moles.
We know number of moles = $\dfrac{{{\text{Given mass}}}}{{{\text{Molar mass}}}}$
Number of moles of benzene = $\dfrac{{7.8}}{{78}}$
Number of moles of benzene = 0.1 moles
Number of moles of toluene = $\dfrac{{{\text{46}}}}{{{\text{92}}}}$
Number of moles of toluene = 0.5 moles
Total number of moles in solution = 0.1 + 0.5
Total number of moles in solution = 0.6 moles
Now, Mole fraction of benzene = $\dfrac{{Number{\text{ of moles of benzene}}}}{{Total{\text{ number of moles of both components}}}}$
Mole fraction of benzene = $\dfrac{{0.1}}{{0.6}}$
Solving the decimals, we get
Mole fraction of benzene = $\dfrac{1}{6}$
Thus, the option a.) is the correct answer.
Note: It must be noted that the total mole fractions of all components of a solution are equal to one. For example - in the above ques, the mole fraction of benzene and mole fraction of toluene will be equal to 1. Further, the molar mass of benzene is 78 and for toluene, it is 92.
$Mole fraction =$ $\dfrac{{Number{\text{ of moles of component}}}}{{Total{\text{ number of moles of all components}}}}$
Complete step by step solution:
First, let us write what is given to us in the question what we need to find out.
Mass of benzene (${C_6}{H_6}$) = 7.8 gm
Mass of toluene (${C_6}{H_5}C{H_3}$) = 46.0 gm
To find : mole fraction of benzene in this solution
Let us first see what is mole fraction.
Mole fraction may be defined as the number of moles of one component divided by the total number of moles of all the components in a solution. It is used to describe the concentration of a species.
Thus, we can write the formulas as -
Mole fraction = $\dfrac{{Number{\text{ of moles of component}}}}{{Total{\text{ number of moles of all components}}}}$
We are given mass of the components. First, we will find its number of moles.
We know number of moles = $\dfrac{{{\text{Given mass}}}}{{{\text{Molar mass}}}}$
Number of moles of benzene = $\dfrac{{7.8}}{{78}}$
Number of moles of benzene = 0.1 moles
Number of moles of toluene = $\dfrac{{{\text{46}}}}{{{\text{92}}}}$
Number of moles of toluene = 0.5 moles
Total number of moles in solution = 0.1 + 0.5
Total number of moles in solution = 0.6 moles
Now, Mole fraction of benzene = $\dfrac{{Number{\text{ of moles of benzene}}}}{{Total{\text{ number of moles of both components}}}}$
Mole fraction of benzene = $\dfrac{{0.1}}{{0.6}}$
Solving the decimals, we get
Mole fraction of benzene = $\dfrac{1}{6}$
Thus, the option a.) is the correct answer.
Note: It must be noted that the total mole fractions of all components of a solution are equal to one. For example - in the above ques, the mole fraction of benzene and mole fraction of toluene will be equal to 1. Further, the molar mass of benzene is 78 and for toluene, it is 92.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

How to find Oxidation Number - Important Concepts for JEE

Half-Life of Order Reactions - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Electromagnetic radiation with maximum wavelength is class 11 chemistry JEE_Main

JEE Main 2025: Derivation of Equation of Trajectory in Physics

The correct order of electron affinity is A F Cl Br class 11 chemistry JEE_Main

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry
