
In a mixed grouping of identical cells, $5$ rows are connected in parallel by each row contains $10$ cells. This combination sends a current ${{i}}$ through an external resistance of ${{20 \Omega }}$. If the emf and internal resistance of each cell is ${{1}}{{.5 V}}$ and $1{{ }}\Omega $, respectively then the value of ${{i}}$ is:
A) 0.14
B) 0.25
C) 0.75
D) 0.68
Answer
207.9k+ views
Hint: When n cells of same emf are connected in series combination the value of current, ${{I = }}\dfrac{{{E}}}{{{r}}}$. When n cells of same emf are connected in parallel combination the value of current, ${{I = }}\dfrac{{{E}}}{{{{R + }}\dfrac{{{r}}}{{{n}}}}}$. Parallel combination of mix grouping of cells, the value of current is given by
${{I = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}$.
Complete step by step solution:
Given: The number of cells in a row, ${{n = 10}}$
The number of rows, ${{m = 5}}$
Emf of each cell, ${{E = 1}}{{.5 V}}$
Internal resistance of each cell, ${{r = 1 \Omega }}$
Electric current is defined as the rate of flow of charge through a conductor in any cross sectional area in a definite direction. SI unit of electric current is ampere represented by A.
Emf is defined as the maximum potential difference between the terminal of the cell when no current is drawn from the cell or the circuit is open. SI unit of emf is voltage represented by V.
Internal resistance is the resistance offered by the electrolyte of the cells to the flow of charge. SI unit of internal resistance is ohms represented by $\Omega $.
Formula for current in mix grouping of cells is given by
$\Rightarrow {{i = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}...{{(i)}}$
Where total resistance ${{ = R + }}\dfrac{{{{nr}}}}{{{m}}}$
Now substituting the given values in formula (i), we get
$
\Rightarrow {{i = }}\dfrac{{{{10 \times 15}}}}{{{{20 + }}\dfrac{{{{10 \times 1}}}}{{{5}}}}} \\
\Rightarrow {{i = }}\dfrac{{{{55}}}}{{{{22}}}} \\
\therefore {{i = 0}}{{.68 A}} $
Note: When the cells are joined in a mix group, then to get the maximum current the load resistance must be equal to the internal resistance of the cell. The value of emf of the cells connected in parallel combination remains the same i.e. ${{{E}}_{{{eqv}}}}{{ = E}}$.
For example: If 2 cells are connected in parallel or 100 cells connected in parallel combination the value of equivalent emf remains the same in both the cases.
${{I = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}$.
Complete step by step solution:
Given: The number of cells in a row, ${{n = 10}}$
The number of rows, ${{m = 5}}$
Emf of each cell, ${{E = 1}}{{.5 V}}$
Internal resistance of each cell, ${{r = 1 \Omega }}$
Electric current is defined as the rate of flow of charge through a conductor in any cross sectional area in a definite direction. SI unit of electric current is ampere represented by A.
Emf is defined as the maximum potential difference between the terminal of the cell when no current is drawn from the cell or the circuit is open. SI unit of emf is voltage represented by V.
Internal resistance is the resistance offered by the electrolyte of the cells to the flow of charge. SI unit of internal resistance is ohms represented by $\Omega $.
Formula for current in mix grouping of cells is given by
$\Rightarrow {{i = }}\dfrac{{{{nE}}}}{{{{R + }}\dfrac{{{{nr}}}}{{{m}}}}}...{{(i)}}$
Where total resistance ${{ = R + }}\dfrac{{{{nr}}}}{{{m}}}$
Now substituting the given values in formula (i), we get
$
\Rightarrow {{i = }}\dfrac{{{{10 \times 15}}}}{{{{20 + }}\dfrac{{{{10 \times 1}}}}{{{5}}}}} \\
\Rightarrow {{i = }}\dfrac{{{{55}}}}{{{{22}}}} \\
\therefore {{i = 0}}{{.68 A}} $
Note: When the cells are joined in a mix group, then to get the maximum current the load resistance must be equal to the internal resistance of the cell. The value of emf of the cells connected in parallel combination remains the same i.e. ${{{E}}_{{{eqv}}}}{{ = E}}$.
For example: If 2 cells are connected in parallel or 100 cells connected in parallel combination the value of equivalent emf remains the same in both the cases.
Recently Updated Pages
Young's Double Slit Experiment Derivation: Stepwise Guide & Formula

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Main 2023 (April 10th Shift 2) Physics Question Paper with Answer Key

JEE Main 2022 (July 28th Shift 1) Physics Question Paper with Answer Key

JEE Main 2023 (January 29th Shift 2) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Correction Window 2026- Edit Form Details, Dates and Link

Atomic Structure: Definition, Models, and Examples

Equation of Trajectory in Projectile Motion: Derivation & Proof

Angle of Deviation in a Prism – Formula, Diagram & Applications

Hybridisation in Chemistry – Concept, Types & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Collision: Meaning, Types & Examples in Physics

How to Convert a Galvanometer into an Ammeter or Voltmeter

Average and RMS Value in Physics: Formula, Comparison & Application

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

