
If\[2X - \left[ {\begin{array}{*{20}{c}}
1&2 \\
7&4
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
3&2 \\
0&{ - 2}
\end{array}} \right]\], then \[X\]is equal to
A. \[\left[ {\begin{array}{*{20}{c}}
2&2 \\
7&4
\end{array}} \right]\]
B. \[\left[ {\begin{array}{*{20}{c}}
1&2 \\
{\dfrac{7}{2}}&2
\end{array}} \right]\]
C. \[\left[ {\begin{array}{*{20}{c}}
2&2 \\
{\dfrac{7}{2}}&1
\end{array}} \right]\]
D. None of these
Answer
217.5k+ views
Hint: We can find the value of 2X by taking the second term to the R.H.S and adding the two matrices. The matrix X can then be found by dividing the matrix thus obtained by 2. When the matrix is divided by 2, each and every term of the matrix gets divided by 2.
Formula used:
If \[A = \left[ {\begin{array}{*{20}{c}}
a&b \\
c&d
\end{array}} \right]\]and \[B = \left[ {\begin{array}{*{20}{c}}
e&f \\
g&h
\end{array}} \right]\] then,
\[
A + B = \left[ {\begin{array}{*{20}{c}}
a&b \\
c&d
\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}
e&f \\
g&h
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
{a + e}&{b + f} \\
{c + g}&{d + h}
\end{array}} \right] \\
\\
\]
Complete step by step solution:
We are given that,
\[2X - \left[ {\begin{array}{*{20}{c}}
1&2 \\
7&4
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
3&2 \\
0&{ - 2}
\end{array}} \right]\]
\[ \Rightarrow 2X = \left[ {\begin{array}{*{20}{c}}
3&2 \\
0&{ - 2}
\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}
1&2 \\
7&4
\end{array}} \right]\]
On adding the two matrices on the R.H.S we get,
\[2X = \left[ {\begin{array}{*{20}{c}}
4&4 \\
7&2
\end{array}} \right]\]
On dividing by 2 on both sides we get,
\[X = \left[ {\begin{array}{*{20}{c}}
2&2 \\
{\dfrac{7}{2}}&1
\end{array}} \right]\]
Option C. is the correct answer.
Note:
To solve the given problem, one must know to add two matrices. When adding two matrices one must make sure the order of the two matrices is the same. If a matrix is divided by a scalar quantity, then the scalar is to be divided by each and every term of the matrix.
Formula used:
If \[A = \left[ {\begin{array}{*{20}{c}}
a&b \\
c&d
\end{array}} \right]\]and \[B = \left[ {\begin{array}{*{20}{c}}
e&f \\
g&h
\end{array}} \right]\] then,
\[
A + B = \left[ {\begin{array}{*{20}{c}}
a&b \\
c&d
\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}
e&f \\
g&h
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
{a + e}&{b + f} \\
{c + g}&{d + h}
\end{array}} \right] \\
\\
\]
Complete step by step solution:
We are given that,
\[2X - \left[ {\begin{array}{*{20}{c}}
1&2 \\
7&4
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
3&2 \\
0&{ - 2}
\end{array}} \right]\]
\[ \Rightarrow 2X = \left[ {\begin{array}{*{20}{c}}
3&2 \\
0&{ - 2}
\end{array}} \right] + \left[ {\begin{array}{*{20}{c}}
1&2 \\
7&4
\end{array}} \right]\]
On adding the two matrices on the R.H.S we get,
\[2X = \left[ {\begin{array}{*{20}{c}}
4&4 \\
7&2
\end{array}} \right]\]
On dividing by 2 on both sides we get,
\[X = \left[ {\begin{array}{*{20}{c}}
2&2 \\
{\dfrac{7}{2}}&1
\end{array}} \right]\]
Option C. is the correct answer.
Note:
To solve the given problem, one must know to add two matrices. When adding two matrices one must make sure the order of the two matrices is the same. If a matrix is divided by a scalar quantity, then the scalar is to be divided by each and every term of the matrix.
Recently Updated Pages
Area vs Volume: Key Differences Explained for Students

Mutually Exclusive vs Independent Events: Key Differences Explained

Addition of Three Vectors: Methods & Examples

Addition of Vectors: Simple Guide for Students

Algebra Made Easy: Step-by-Step Guide for Students

Relations and Functions: Complete Guide for Students

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Understanding Atomic Structure for Beginners

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding the Electric Field of a Uniformly Charged Ring

