
If the unit of force is kN, the length is 1 km and for the time it is 100s, then what will be the unit of mass?
(A) 1000 kg
(B) 1 kg
(C) 10000 kg
(D) 100 kg
Answer
239.4k+ views
Hint: We know the standard SI unit of force is newtons (N), for length it is meters (m) and for time it is seconds (s). Now we are given that the unit of force is to be kilo Newton, for length it is 1km and for time it is 100s. we can make use of dimensional analysis to solve this problem.
Complete step by step solution:
We know force is given by the formula, $F=ma$
\[F=[ML{{T}^{-2}}]\]
$\Rightarrow 1000N=\dfrac{M\times 1000m}{{{(100s)}^{2}}} \\
\Rightarrow M=10000kg \\$
So, the correct option is (c)
Additional Information: Method of Dimensional analysis is also called Factor Label Method. The method of dimensional analysis is of great use as we can check the correctness of Physical Equation by using it. However, it should be kept in mind that dimensional analysis cannot help us determine any dimensionless constants in the equation. The method when used in chemistry there in place of using designated symbols we use units.
Note: There are few drawbacks for this method, although this method is widely used. This method cannot be used when we are dealing with the dimensionless quantities. Constant proportionality cannot be determined by this method. It does not apply to trigonometric, logarithmic and exponential functions physical quantities which are dependent upon more than three physical quantities, this method will be difficult.
Complete step by step solution:
We know force is given by the formula, $F=ma$
\[F=[ML{{T}^{-2}}]\]
$\Rightarrow 1000N=\dfrac{M\times 1000m}{{{(100s)}^{2}}} \\
\Rightarrow M=10000kg \\$
So, the correct option is (c)
Additional Information: Method of Dimensional analysis is also called Factor Label Method. The method of dimensional analysis is of great use as we can check the correctness of Physical Equation by using it. However, it should be kept in mind that dimensional analysis cannot help us determine any dimensionless constants in the equation. The method when used in chemistry there in place of using designated symbols we use units.
Note: There are few drawbacks for this method, although this method is widely used. This method cannot be used when we are dealing with the dimensionless quantities. Constant proportionality cannot be determined by this method. It does not apply to trigonometric, logarithmic and exponential functions physical quantities which are dependent upon more than three physical quantities, this method will be difficult.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

Trending doubts
JEE Main 2026: Session 1 Results Out and Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Angle of Deviation in a Prism

Understanding Electromagnetic Waves and Their Importance

Hybridisation in Chemistry – Concept, Types & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

CBSE Notes Class 11 Physics Chapter 14 - Waves - 2025-26

CBSE Notes Class 11 Physics Chapter 9 - Mechanical Properties of Fluids - 2025-26

CBSE Notes Class 11 Physics Chapter 11 - Thermodynamics - 2025-26

