
If ${\log _{10}}\left( {x - 10} \right) = 1$, then the value of x is equal to:
$
{\text{A}}{\text{. 20}} \\
{\text{B}}{\text{. 30}} \\
{\text{C}}{\text{. 40}} \\
{\text{D}}{\text{. 50}} \\
$
Answer
241.2k+ views
Hint- In this question we have to find the value of x so using the property of logarithm we know that ${\log _b}a = 1 \Rightarrow {b^1} = a$. This property will help you simplify things up and will eventually help you reach the right answer.
We have been given the expression ${\log _{10}}\left( {x - 10} \right) = 1$ and we have to find the value of x.
Now we know the property of logarithm that ${\log _b}a = 1 \Rightarrow {b^1} = a$ ………………….. (1)
So using the property mentioned in equation (1) to the given expression of question we get
${10^1} = \left( {x - 10} \right)$
On solving
$10 = x - 10$
$ \Rightarrow x = 20$
Hence the value of x = 20
Thus option (a) is the right answer to this answer.
Note- Whenever we face such types of problems the key point to remember is that we need to have a good grasp over the logarithmic identities, some of them have been mentioned above. These identities help you in simplification and getting on the right track to reach the answer.
We have been given the expression ${\log _{10}}\left( {x - 10} \right) = 1$ and we have to find the value of x.
Now we know the property of logarithm that ${\log _b}a = 1 \Rightarrow {b^1} = a$ ………………….. (1)
So using the property mentioned in equation (1) to the given expression of question we get
${10^1} = \left( {x - 10} \right)$
On solving
$10 = x - 10$
$ \Rightarrow x = 20$
Hence the value of x = 20
Thus option (a) is the right answer to this answer.
Note- Whenever we face such types of problems the key point to remember is that we need to have a good grasp over the logarithmic identities, some of them have been mentioned above. These identities help you in simplification and getting on the right track to reach the answer.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 1 Results Out and Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Clemmensen and Wolff Kishner Reductions Explained for JEE & NEET

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding the Angle of Deviation in a Prism

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

Inductive Effect and Its Role in Acidic Strength

Hybridisation in Chemistry – Concept, Types & Applications

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Understanding the Electric Field of a Uniformly Charged Ring

