Question

When ${{I}_{2}}$ ​ is dissolved in $CC{{l}_{4}}$ the colour that results is
A. Brown
B. Violet
C. Colourless
D. Bluish green

Answer 1

Hint: If we see the reactivity trend of halogens then iodine is the least reactive and chlorine is the most reactive among the halogens. Thus it can’t liberate any halogen and remain unreactive.

Complete Step by Step Answer:
Iodine is a covalent compound and the carbon tetrachloride is a non polar compound. Thus iodine gas easily dissolves in nonpolar carbon tetrachloride solution but it does not react with carbon tetrachloride solution. So, the iodine remains and the solution gives violet colour that is the colour of iodine vapour. Thus we can write that when ${{I}_{2}}$ ​ is dissolved in $CC{{l}_{4}}$ the colour that results is violet.
Thus the correct option is B.

Additional Information: Iodine is a halogen element. It has the symbol of $I$. It generally exists as a gas. It has the colour of violet blue. Iodine is generally obtained from seaweed. Starch generally acts as an indicator in titration reactions to determine the end point of a titration. Iodine gas reacts with starch, an indicator gives blue colour.

Note: Carbon tetrachloride is a non polar solvent. Thus any covalent compound can easily dissolve in it. Again water is a polar solvent so, the covalent iodine will not dissolve in water.