
What happens when concentrated \[HN{O_3}\] is added to iron metal?
A)Nitrogen is given out
B)Hydrogen is given out
C)The metal becomes passive
D)\[Fe{(N{O_3})_2}\] is formed
Answer
224.7k+ views
Hint:Nitric Acid or \[HN{O_3}\] is a highly corrosive mineral acid. It exhibits different characteristics while reacting with different substances. The type of products formed in the reactions involving \[HN{O_3}\] varies greatly depending on the concentration of \[HN{O_3}\] . When the concentration of nitric acid is dilute, it behaves like any other regular acid
Complete Step-by-Step Answer:
Before we move forward with the solution of the given question, let us understand some important basic concepts.
When a metal is reacted with dilute nitric acid, it results in the formation of the corresponding metal nitrate. This reaction also involves the release of hydrogen gas. A general representation of the chemical reaction between a metal and dilute nitric acid can be given as:
\[M + 2HN{O_3} \to M{(N{O_3})_2} + {H_2}\] , where M is the metal.
Now, when a concentrated solution of the acid is used, it usually results in the oxidizing of the products and also releases nitrogen dioxide gas as a by – product. When this highly concentrated nitric acid is reacted with metals like aluminium, chromium, or iron, they generally tend to dissolve in the acid solution. Nitric acid forms a layer of metal oxide on the surfaces of these metals, which tends to protect the bigger bulk of the metal. The process of formation of this protective layer because of concentrated nitric acid is known as Passivation. Hence, the metal becomes chemically passive because of reacting with concentrated nitric acid.
Hence, Option C is the correct option
Note: Metals such as gold, Platinum do not react with nitric acid. They do not react with any strong acids for that matter. This is because the reactivity of these metals is extremely low. However, these metals react with a compound named Aqua Regia. Aqua Regia is made form nitric acid and hydrochloric acid.
Complete Step-by-Step Answer:
Before we move forward with the solution of the given question, let us understand some important basic concepts.
When a metal is reacted with dilute nitric acid, it results in the formation of the corresponding metal nitrate. This reaction also involves the release of hydrogen gas. A general representation of the chemical reaction between a metal and dilute nitric acid can be given as:
\[M + 2HN{O_3} \to M{(N{O_3})_2} + {H_2}\] , where M is the metal.
Now, when a concentrated solution of the acid is used, it usually results in the oxidizing of the products and also releases nitrogen dioxide gas as a by – product. When this highly concentrated nitric acid is reacted with metals like aluminium, chromium, or iron, they generally tend to dissolve in the acid solution. Nitric acid forms a layer of metal oxide on the surfaces of these metals, which tends to protect the bigger bulk of the metal. The process of formation of this protective layer because of concentrated nitric acid is known as Passivation. Hence, the metal becomes chemically passive because of reacting with concentrated nitric acid.
Hence, Option C is the correct option
Note: Metals such as gold, Platinum do not react with nitric acid. They do not react with any strong acids for that matter. This is because the reactivity of these metals is extremely low. However, these metals react with a compound named Aqua Regia. Aqua Regia is made form nitric acid and hydrochloric acid.
Recently Updated Pages
JEE Main 2025-26 Mock Test: Organic Compounds Containing Nitrogen

JEE Main 2025-26 Organic Compounds Containing Nitrogen Mock Test

JEE Main Chemical Kinetics Mock Test 2025-26: Free Practice Online

JEE Main 2025-26 Organic Compounds Containing Oxygen Mock Test

JEE Main 2025-26 Organic Compounds Containing Halogens Mock Test

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 4 The D and F Block Elements

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

