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# Four massless springs whose force constants are 2k, 2k, k and 2k respectively are attached to a mass M kept on a frictionless plane as shown in the figure. If the mass M is displaced in the horizontal direction, then the frequency of the system is:A) $\dfrac{1}{{2\pi }}\sqrt {\dfrac{k}{{4M}}}$ B) $\dfrac{1}{{2\pi }}\sqrt {\dfrac{{4k}}{M}}$ C) $\dfrac{1}{{2\pi }}\sqrt {\dfrac{k}{{7M}}}$ D) $\dfrac{1}{{2\pi }}\sqrt {\dfrac{{7k}}{{7M}}}$

Last updated date: 13th Jul 2024
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Hint: Formula for frequency is:
$\dfrac{1}{{2\pi }}\sqrt {\dfrac{1}{{LC}}}$ (L is the inductor, C is the capacitor)
As per electrical and mechanical analogy conversion, in force current analogy M is the capacitor (C) and k is the reciprocal of the inductor (1/L).
Let’s find the value of k using series and parallel connections (using 1/L = k, in series connections are added with their direct connections and the parallel connection have reciprocal addition).

Complete step by step solution:
As we are provided with an inductor and capacitor in the system then we will add the reciprocal of the inductor for the series connection.
$K = {K_1} + {K_2}$
First, we will do the calculation for series connection:
$\Rightarrow {K_1} = \dfrac{1}{{2k}} + \dfrac{1}{{2k}} \\ \Rightarrow {K_1} = \dfrac{{2k \times 2k}}{{2k + 2k}}$ (Taking LCM)
$\Rightarrow {K_1} = \dfrac{{2k}}{{2k}} = 1k$
Now, we will calculate for the springs in parallel:
$\Rightarrow {K_2} = \dfrac{1}{{\dfrac{1}{{2k}}}} + \dfrac{1}{{\dfrac{1}{k}}} \\ \Rightarrow {K_2} = 2k + k = 3k$ (in parallel connection we have to take the reciprocal of the spring constants)
Total value of K comes out to be:
$\Rightarrow K = {K_1} + {K_2} \\ \Rightarrow K = k + 3k = 4k$
From the equation of frequency:
$\Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{1}{{M\dfrac{1}{K}}}} \\ \Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{K}{M}}$ (We have substituted the value of LC as per formula of frequency)
$\Rightarrow f = \dfrac{1}{{2\pi }}\sqrt {\dfrac{{4k}}{M}}$ (We have substituted the values M and K).

Hence, Option B is correct.

Note: In the question above we have used electrical to mechanical equivalent system of force current, where current is acting as the force in a mechanical system, mass as capacitor, frictional coefficient as reciprocal of R resistor, spring constant as reciprocal of L inductor, displacement as magnetic flux and velocity as voltage.