
For an RLC circuit, driven with voltage of amplitude $vm$ and frequency ${\omega _0} = \dfrac{1}{{\sqrt {LC} }}$ the current exhibits resonance. The quality factor, $Q$ is given by
a) $\dfrac{R}{{({\omega _0}C)}}$
b) $\dfrac{{CR}}{{{\omega _0}}}$
c) $\dfrac{{{\omega _0}L}}{R}$
d) $\dfrac{{{\omega _0}R}}{L}$
Answer
232.8k+ views
Hint: The quality factor is defined as the voltage magnification of the circuit at resonance. Electrical resonance occurs in an electric circuit at a particular resonant frequency when the impedances or admittances of circuit elements cancel each other.
Complete step by step answer:
Let’s define all the data given in the question:
Voltage amplitude $ = vm$
Frequency, ${\omega _0} = \dfrac{1}{{\sqrt {LC} }}$
It is given that the current exhibits resonance.
Thus frequency ${\omega _0}$when subjected to resonance:
$ \Rightarrow {\omega _0} = \dfrac{1}{{\sqrt {LC} }}\left\{ {{X_L} = {X_C}} \right\}$
We need to find the quality factor, $Q$
The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth.
The quality factor, Q is given by, $Q = \dfrac{{{\omega _0}}}{{Bw}}$
Where, $Bw = $Band width,
We know the value of bandwidth by the formula,
$Bw = \dfrac{R}{L}$
Applying this value of band width to the formula of the quality factor, we get,
$ \Rightarrow Q = \dfrac{{{\omega _0}}}{{Bw}}$
$ \Rightarrow Q = \dfrac{{{\omega _0}L}}{R}$
From The above equation, we get the value for the quality factor, that is,
The quality factor, $Q = \dfrac{{{\omega _0}L}}{R}$
So the final answer will be Option(C).
Note: A resonant L-C-R circuit’s sharpness of resonance can be determined by the ratio of resonant frequency with the selectivity of the circuit. And this ratio is called the Quality Factor or the Q-factor. The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth, which is desirable in many applications. More formally, Q is the ratio of power stored to power dissipated in the circuit.
Complete step by step answer:
Let’s define all the data given in the question:
Voltage amplitude $ = vm$
Frequency, ${\omega _0} = \dfrac{1}{{\sqrt {LC} }}$
It is given that the current exhibits resonance.
Thus frequency ${\omega _0}$when subjected to resonance:
$ \Rightarrow {\omega _0} = \dfrac{1}{{\sqrt {LC} }}\left\{ {{X_L} = {X_C}} \right\}$
We need to find the quality factor, $Q$
The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth.
The quality factor, Q is given by, $Q = \dfrac{{{\omega _0}}}{{Bw}}$
Where, $Bw = $Band width,
We know the value of bandwidth by the formula,
$Bw = \dfrac{R}{L}$
Applying this value of band width to the formula of the quality factor, we get,
$ \Rightarrow Q = \dfrac{{{\omega _0}}}{{Bw}}$
$ \Rightarrow Q = \dfrac{{{\omega _0}L}}{R}$
From The above equation, we get the value for the quality factor, that is,
The quality factor, $Q = \dfrac{{{\omega _0}L}}{R}$
So the final answer will be Option(C).
Note: A resonant L-C-R circuit’s sharpness of resonance can be determined by the ratio of resonant frequency with the selectivity of the circuit. And this ratio is called the Quality Factor or the Q-factor. The goodness or quality of a resonant circuit is described by the term quality factor, Q of a resonant circuit. If the figure is a higher value that corresponds to a narrower bandwidth, which is desirable in many applications. More formally, Q is the ratio of power stored to power dissipated in the circuit.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

