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Faraday’s second law states that mass deposited on the electrode is directly proportional to
A. Atomic Mass
B. Atomic Mass\[\times \] velocity
C. \[\dfrac{{Atomic \ Mass}}{{Valency}}\]
D. Valency

Answer
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Hint: In electrolysis, a chemical compound is decomposed when a chemical reaction occurs on passing electric current. In this reaction, one substance loses and the other substance gains electrons. An electrolyte is the solution through which the electric current is passed.

Complete Step by Step Answer:
Faraday’s second law of electrolysis states that if there are two different electrolytes through which same amount of electricity is passed then the mass of ions that gets deposited at the electrodes varies directly with the chemical equivalents.
\[w \propto E\]
w=mass of the substance
E= Equivalent weight of the substance
The equivalent weight can be written as the ratio of its atomic weight and valency of the substance.
\[E = \dfrac{{AtomicMass}}{{Valency}}\]
So, the mass deposited on the electrode varies directly with atomic mass and inversely with the valency.
Therefore, Option C is the correct answer.

Note: Faraday’s laws of electromagnetic induction were first proposed by Michael Faraday in 1833 while he was experimenting and studying for electrolysis of solutions. Electrolysis is a non spontaneous reduction-oxidation reaction in which electricity is used. Faraday proposed two laws for the study of electrolysis. According to the First law of Faraday, the amount of reaction occurring on passing electric current is directly proportional to the amount of electricity passed through the solution. In electrolysis when current enters or leaves the circuit, that point is the electrode and there are two electrodes. When the current enters the solution that point is known as anode and when the current leaves the circuit that point is known as cathode.