
Evaluate the integral $\int {x\log x dx} $
A. $\dfrac{{{x^2}}}{4}\left( {2\log x - 1} \right) + c$
B. $\dfrac{{{x^2}}}{2}\left( {2\log x - 1} \right) + c$
C. $\dfrac{{{x^2}}}{4}\left( {2\log x + 1} \right) + c$
D. $\dfrac{{{x^2}}}{2}\left( {2\log x + 1} \right) + c$
Answer
163.2k+ views
Hint: The given integrand is a product of two functions $x$ and $\log x$. Use by parts the rule of integration taking $\log x$ as first function and $x$ as second function to evaluate the integral.
Formula Used:
The by parts rule of the integration of product of two functions $u\left( x \right)$ and $v\left( x \right)$ is $\int {u\left( x \right)v\left( x \right)dx = u\left( x \right)\int {v\left( x \right)dx - \int {\left[ {\dfrac{d}{{dx}}\left\{ {u\left( x \right)} \right\}\int {v\left( x \right)dx} } \right]} dx} } $, where the functions $u\left( x \right)$ and $v\left( x \right)$ are chosen according to ILATE rule.
Complete step by step solution:
Let $u\left( x \right) = \log x$ and $v\left( x \right) = x$
Then the given integral is
$\int {x\log x dx = \int {\log x \cdot xdx} } $
Use the by parts rule
$\log x\int {\left( x \right)dx - \int {\left\{ {\dfrac{d}{{dx}}\left( {\log x} \right)\int {xdx} } \right\}} } dx.....(i)$
Use the formula $\int {\left( {{x^n}} \right)dx = } \dfrac{{{x^{n + 1}}}}{{n + 1}} + c$ and $\dfrac{d}{{dx}}\left( {\log x} \right) = \dfrac{1}{x}$
Putting $n = 1$, we get
$\int {xdx = \dfrac{{{x^2}}}{2} + c} $
Now, from $(i)$, we get
$\int {x\log xdx} \\ \Rightarrow \log x\left( {\dfrac{{{x^2}}}{2}} \right) - \int {\left( {\dfrac{1}{x} \cdot \dfrac{{{x^2}}}{2}} \right)} dx\\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{1}{2}\int {xdx} \\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{1}{2}\left( {\dfrac{{{x^2}}}{2}} \right) + c\\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{{{x^2}}}{4} + c\\ \Rightarrow \dfrac{{{x^2}}}{4}\left( {2\log x - 1} \right) + c$
Option ‘A’ is correct
Note: Consider using the ILATE property when selecting the first and second functions, and remember that the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function. For indefinite integrals, the integration constant must be used.
Formula Used:
The by parts rule of the integration of product of two functions $u\left( x \right)$ and $v\left( x \right)$ is $\int {u\left( x \right)v\left( x \right)dx = u\left( x \right)\int {v\left( x \right)dx - \int {\left[ {\dfrac{d}{{dx}}\left\{ {u\left( x \right)} \right\}\int {v\left( x \right)dx} } \right]} dx} } $, where the functions $u\left( x \right)$ and $v\left( x \right)$ are chosen according to ILATE rule.
Complete step by step solution:
Let $u\left( x \right) = \log x$ and $v\left( x \right) = x$
Then the given integral is
$\int {x\log x dx = \int {\log x \cdot xdx} } $
Use the by parts rule
$\log x\int {\left( x \right)dx - \int {\left\{ {\dfrac{d}{{dx}}\left( {\log x} \right)\int {xdx} } \right\}} } dx.....(i)$
Use the formula $\int {\left( {{x^n}} \right)dx = } \dfrac{{{x^{n + 1}}}}{{n + 1}} + c$ and $\dfrac{d}{{dx}}\left( {\log x} \right) = \dfrac{1}{x}$
Putting $n = 1$, we get
$\int {xdx = \dfrac{{{x^2}}}{2} + c} $
Now, from $(i)$, we get
$\int {x\log xdx} \\ \Rightarrow \log x\left( {\dfrac{{{x^2}}}{2}} \right) - \int {\left( {\dfrac{1}{x} \cdot \dfrac{{{x^2}}}{2}} \right)} dx\\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{1}{2}\int {xdx} \\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{1}{2}\left( {\dfrac{{{x^2}}}{2}} \right) + c\\ \Rightarrow \dfrac{{{x^2}}}{2}\log x - \dfrac{{{x^2}}}{4} + c\\ \Rightarrow \dfrac{{{x^2}}}{4}\left( {2\log x - 1} \right) + c$
Option ‘A’ is correct
Note: Consider using the ILATE property when selecting the first and second functions, and remember that the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function. For indefinite integrals, the integration constant must be used.
Recently Updated Pages
Geometry of Complex Numbers – Topics, Reception, Audience and Related Readings

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Maths Chapter 4 Complex Numbers and Quadratic Equations

Instantaneous Velocity - Formula based Examples for JEE

NCERT Solutions for Class 11 Maths Chapter 6 Permutations and Combinations

NCERT Solutions for Class 11 Maths Chapter 8 Sequences and Series
