Arrange the following phenols in increasing order of ${\text{p}}{{\text{K}}_{{\text{a1}}}}$ value.

A. IB. IIIC. IIID. I
Answer
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Hint: Electron donating substituents tend to decrease the acidic strength while electron withdrawing substituents tend to increase the acidic strength of substituted phenols relative to phenol.
The acid strengthening effect of the electron withdrawing substituents and the acid weakening effect of the electron donating substituents are more pronounced at the ortho and the para positions.
Complete step by step answer:
Nitro group has a powerful electron withdrawing resonance effect or –R effect as well as an electron withdrawing inductive effect or –I effect. As a result, all the nitrophenols are stronger acids than phenol.
Therefore, the acid strengthening effect of the electron withdrawing nitro group will be less pronounced at the meta position of the ring in comparison to that at the ortho and para positions. So, the nitro group will decrease the electron density more at the ortho and para positions than at the meta position.
Thus, the conjugate base nitro phenoxide ion will have lesser stabilization in case of the meta isomer than in the case of ortho and para isomers. So, only the weaker –I effect will be responsible for electron withdrawing at meta position. Thus, meta nitrophenol will be the weakest acid among the three.
Now, we are left with ortho- and para- nitrophenol. In case of ortho nitrophenol, intramolecular hydrogen bonding occurs between the adjacent hydroxyl and the nitro group. Thus, the removal of a proton is difficult in the ortho isomer and so it is a weaker acid than the para isomer.

Thus, the acidic strength increases in the order: meta< ortho< para.
Since higher ${\text{p}}{{\text{K}}_{\text{a}}}$ value indicates a weaker acid, thus the order of ${\text{p}}{{\text{K}}_{\text{a}}}$ values will be para< ortho< meta or III< II< I.
So the correct option is C.
Note:
Ortho effect is the effect which makes the ortho substituted benzoic acids stronger acids than benzoic acid regardless of the nature of the substituent.
In case of nitrobenzoic acid, the ortho nitrobenzoic acid will be the strongest acid due to ortho effect while the meta isomer will be now a weaker acid only in comparison to the para isomer.
Thus, the acidic strength of nitrobenzoic acids will be: meta< para< ortho.
The acid strengthening effect of the electron withdrawing substituents and the acid weakening effect of the electron donating substituents are more pronounced at the ortho and the para positions.
Complete step by step answer:
Nitro group has a powerful electron withdrawing resonance effect or –R effect as well as an electron withdrawing inductive effect or –I effect. As a result, all the nitrophenols are stronger acids than phenol.
Therefore, the acid strengthening effect of the electron withdrawing nitro group will be less pronounced at the meta position of the ring in comparison to that at the ortho and para positions. So, the nitro group will decrease the electron density more at the ortho and para positions than at the meta position.
Thus, the conjugate base nitro phenoxide ion will have lesser stabilization in case of the meta isomer than in the case of ortho and para isomers. So, only the weaker –I effect will be responsible for electron withdrawing at meta position. Thus, meta nitrophenol will be the weakest acid among the three.
Now, we are left with ortho- and para- nitrophenol. In case of ortho nitrophenol, intramolecular hydrogen bonding occurs between the adjacent hydroxyl and the nitro group. Thus, the removal of a proton is difficult in the ortho isomer and so it is a weaker acid than the para isomer.

Thus, the acidic strength increases in the order: meta< ortho< para.
Since higher ${\text{p}}{{\text{K}}_{\text{a}}}$ value indicates a weaker acid, thus the order of ${\text{p}}{{\text{K}}_{\text{a}}}$ values will be para< ortho< meta or III< II< I.
So the correct option is C.
Note:
Ortho effect is the effect which makes the ortho substituted benzoic acids stronger acids than benzoic acid regardless of the nature of the substituent.
In case of nitrobenzoic acid, the ortho nitrobenzoic acid will be the strongest acid due to ortho effect while the meta isomer will be now a weaker acid only in comparison to the para isomer.
Thus, the acidic strength of nitrobenzoic acids will be: meta< para< ortho.
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