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An acyl halide is formed when \[PC{l_5}\] reacts with an:
A. Acid
B. Alcohol
C. Amide
D. Ester

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Last updated date: 14th Apr 2024
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MVSAT 2024
Answer
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Hint: Let us first understand some basic concepts before we proceed with the solution for this question:
Acyl halides can be explained as the halogen substituted hydroxyl groups in organic compounds. Acyl halides are basically formed when the hydroxy or the -OH group of the hydroxyl or -COOH group gets replaced by a halogen. This is a basic substitution reaction.

Complete Step-by-Step Answer:
In order to solve this question, we must find the products formed by \[PC{l_5}\] with all the given options.
Reaction with acid: the reaction of \[PC{l_5}\] with a given acid would result in the formation of acid chlorides in the products. Acid chloride is the common name for acyl halide where chlorine is the halogen.

Reaction with alcohol: alcohols react in a rather violent manner with \[PC{l_5}\], resulting in the emissive release of hydrochloric acid.
 \[R - OH + PC{l_5} \to R - Cl + POC{l_3} + HCl\]

Reaction with amide: when amides are reacted with \[PC{l_5}\], it results in the dehydration of the amide. The corresponding reaction can be given as:
\[R - CON{H_2} + PC{l_5} \to R - C{(Cl)_2}N{H_2} + PC{l_3}\]

Reaction with esters: reaction between esters and \[PC{l_5}\] results in the formation of an alkyl halide, an acyl halide and also phosphorous oxychloride. Hence, only acyl halide cannot be obtained from esters.


Hence, Option A is the correct option.

Note: In the reaction of \[PC{l_5}\] with carboxylic acid, the reaction goes firstly by a cyclic transition state with the removal of HCl. Then via a nucleophilic addition of chloride where the carbonyl is simultaneously protonated.