Answer
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Hint: Let us first understand some basic concepts before we proceed with the solution for this question:
Acyl halides can be explained as the halogen substituted hydroxyl groups in organic compounds. Acyl halides are basically formed when the hydroxy or the -OH group of the hydroxyl or -COOH group gets replaced by a halogen. This is a basic substitution reaction.
Complete Step-by-Step Answer:
In order to solve this question, we must find the products formed by \[PC{l_5}\] with all the given options.
Reaction with acid: the reaction of \[PC{l_5}\] with a given acid would result in the formation of acid chlorides in the products. Acid chloride is the common name for acyl halide where chlorine is the halogen.
Reaction with alcohol: alcohols react in a rather violent manner with \[PC{l_5}\], resulting in the emissive release of hydrochloric acid.
\[R - OH + PC{l_5} \to R - Cl + POC{l_3} + HCl\]
Reaction with amide: when amides are reacted with \[PC{l_5}\], it results in the dehydration of the amide. The corresponding reaction can be given as:
\[R - CON{H_2} + PC{l_5} \to R - C{(Cl)_2}N{H_2} + PC{l_3}\]
Reaction with esters: reaction between esters and \[PC{l_5}\] results in the formation of an alkyl halide, an acyl halide and also phosphorous oxychloride. Hence, only acyl halide cannot be obtained from esters.
Hence, Option A is the correct option.
Note: In the reaction of \[PC{l_5}\] with carboxylic acid, the reaction goes firstly by a cyclic transition state with the removal of HCl. Then via a nucleophilic addition of chloride where the carbonyl is simultaneously protonated.
Acyl halides can be explained as the halogen substituted hydroxyl groups in organic compounds. Acyl halides are basically formed when the hydroxy or the -OH group of the hydroxyl or -COOH group gets replaced by a halogen. This is a basic substitution reaction.
Complete Step-by-Step Answer:
In order to solve this question, we must find the products formed by \[PC{l_5}\] with all the given options.
Reaction with acid: the reaction of \[PC{l_5}\] with a given acid would result in the formation of acid chlorides in the products. Acid chloride is the common name for acyl halide where chlorine is the halogen.
Reaction with alcohol: alcohols react in a rather violent manner with \[PC{l_5}\], resulting in the emissive release of hydrochloric acid.
\[R - OH + PC{l_5} \to R - Cl + POC{l_3} + HCl\]
Reaction with amide: when amides are reacted with \[PC{l_5}\], it results in the dehydration of the amide. The corresponding reaction can be given as:
\[R - CON{H_2} + PC{l_5} \to R - C{(Cl)_2}N{H_2} + PC{l_3}\]
Reaction with esters: reaction between esters and \[PC{l_5}\] results in the formation of an alkyl halide, an acyl halide and also phosphorous oxychloride. Hence, only acyl halide cannot be obtained from esters.
Hence, Option A is the correct option.
Note: In the reaction of \[PC{l_5}\] with carboxylic acid, the reaction goes firstly by a cyclic transition state with the removal of HCl. Then via a nucleophilic addition of chloride where the carbonyl is simultaneously protonated.
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