Question

Ammonium chloride on reaction with NaOH gives :
A. Ammonia
B. Sodium chloride
C. Water
D. All of the above

Answer 1

Hint: Chemical formula is a way to write a substance using the chemical symbol and number subscripts to mention the number of the atoms into that chemical compound. Ammonium chloride is an inorganic salt. The formula of ammonium chloride is \[{\text{N}}{{\text{H}}_{\text{4}}}{\text{Cl}}\]. The ammonium chloride can be formed by the reaction of hydrochloric acid and ammonia as follows.
 \[N{H_3}\, + HCl \to N{H_4}Cl\]

Complete step by step answer:
Ammonium chloride can be formed by the reaction of ammonia and hydrochloric acid.
On the reaction of Ammonium chloride with NaOH, it forms salt sodium chloride, water, and ammonia. The reaction is shown below.
 \[N{H_4}Cl + NaOH\xrightarrow{{Heat}}NaCl + N{H_{3}} + {H_{2}}O\]
Therefore, all of those in the given options are formed.

So, the correct option is D.

Additional information:
The Heber process is used to prepare ammonia. In this reaction, nitrogen and hydrogen gas is used and to the catalyst, the reaction solid iron is used. This mechanism is also exothermic. The reaction is shown below,
 \[{N_2}(g) + 3{H_2}(g)\xrightarrow{{Fe}}2N{H_3}(g)\]

Note:
Ammonium nitrate is an inorganic compound. The formula of ammonium nitrate is \[{\text{N}}{{\text{H}}_{\text{4}}}{\text{N}}{{\text{O}}_{\text{3}}}\]. When Solid ammonium nitrate is heated, it decomposes into gas very rapidly. Ammonium nitrate decomposes into nitrous oxide and water vapor.
The reaction of decomposition is
 \[N{H_4}N{O_3}\left( s \right) \to {N_2}O(g) + 2{H_2}O(g)\].
This decomposition is exothermic with the value of \[\Delta H = - 36kJ/mol\].