
All wires have the same resistance and equivalent resistance between A and B is ${R_y}$. Now keys are closed, then the equivalent resistance will become

A. \[\frac{{7{R_0}}}{3}\]
B. \[\frac{{7{R_0}}}{9}\]
C. \[7{R_0}\]
D. \[\frac{{{R_0}}}{3}\]
Answer
218.1k+ views
Hint: We understand how to solve resistor series and parallel combinations in any circuit. However, in this case, we have resistors in both parallel and series configurations. To solve this type of problem, we must divide it into series components and solve it repeatedly. The resistance in these circuits is estimated by resolving them piece by piece.
Formula used:
Parallel resistance’s equivalent resistance formula:
\[\frac{1}{{{{\rm{R}}_{{\rm{eq }}}}}} = \frac{1}{{{{\rm{R}}_{{\rm{1 }}}}}} + \frac{1}{{{{\rm{R}}_{{\rm{2 }}}}}} + \frac{1}{{{{\rm{R}}_{{\rm{3 }}}}}} + .....\]
Complete answer:
We have been provided in the given data that,
All wires have the same resistance and equivalent resistance between A and B is Ry.
Let us restructure the given circuit by breaking the circuit to simpler circuits for easy understanding, we have


Now, we have to calculate the equivalent resistance, for that we can write as
\[\frac{{{\rm{7}}{{\rm{R}}_{{\rm{0 }}}}}}{3} = {{\rm{R}}_{{\rm{eq }}}}\]
As, from the given circuit it is understood that,
\[{{\rm{R}}_{{\rm{0 }}}} = \frac{{\rm{R}}}{3}\]
Now, we have substitute the value obtained before, we get
\[{{\rm{R}}_{{\rm{eq }}}} = \frac{{7{\rm{R}}}}{9}\]
Therefore, when keys are closed, then the equivalent resistance will become \[{{\rm{R}}_{{\rm{eq }}}} = \frac{{7{\rm{R}}}}{9}\]
Hence, option B is the correct answer
Note:All wires have the same resistance and equivalent resistance between A and B is \[Ry\], then when keys are closed, the equivalent resistance will become \[\frac{{7{R_0}}}{9}\].
To generate the same impact on the circuit by allowing the same amount of current, one resistor can be used in place of two or more. This is referred to as efficient resistance.
Formula used:
Parallel resistance’s equivalent resistance formula:
\[\frac{1}{{{{\rm{R}}_{{\rm{eq }}}}}} = \frac{1}{{{{\rm{R}}_{{\rm{1 }}}}}} + \frac{1}{{{{\rm{R}}_{{\rm{2 }}}}}} + \frac{1}{{{{\rm{R}}_{{\rm{3 }}}}}} + .....\]
Complete answer:
We have been provided in the given data that,
All wires have the same resistance and equivalent resistance between A and B is Ry.
Let us restructure the given circuit by breaking the circuit to simpler circuits for easy understanding, we have


Now, we have to calculate the equivalent resistance, for that we can write as
\[\frac{{{\rm{7}}{{\rm{R}}_{{\rm{0 }}}}}}{3} = {{\rm{R}}_{{\rm{eq }}}}\]
As, from the given circuit it is understood that,
\[{{\rm{R}}_{{\rm{0 }}}} = \frac{{\rm{R}}}{3}\]
Now, we have substitute the value obtained before, we get
\[{{\rm{R}}_{{\rm{eq }}}} = \frac{{7{\rm{R}}}}{9}\]
Therefore, when keys are closed, then the equivalent resistance will become \[{{\rm{R}}_{{\rm{eq }}}} = \frac{{7{\rm{R}}}}{9}\]
Hence, option B is the correct answer
Note:All wires have the same resistance and equivalent resistance between A and B is \[Ry\], then when keys are closed, the equivalent resistance will become \[\frac{{7{R_0}}}{9}\].
To generate the same impact on the circuit by allowing the same amount of current, one resistor can be used in place of two or more. This is referred to as efficient resistance.
Recently Updated Pages
Young’s Double Slit Experiment Derivation Explained

Wheatstone Bridge Explained: Working, Formula & Uses

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

