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**Hint:**While calculating work done in a rotational motion, we need to consider all the angular equivalents of linear parameters. Maximum angular calculations are done in radians not in degrees.

**Complete step by step answer:**

In rotational motion the angular equivalents of linear parameters are,

$

S \to \theta \\

v \to \omega \\

a \to \alpha \\

F \to \tau $

So, To find work done, we need to find torque$\left( \tau \right)$ first,

$\Rightarrow \tau = r \times F$

$\Rightarrow \tau = 3 \times 200$

$\Rightarrow \tau = 600Nm$

Now to calculate work done by the man,

$\Rightarrow W = \int {\tau d\theta } $

Since torque is constant,

$\Rightarrow W = \tau \Delta \theta $

In this case total angular displacement$\left( \theta \right)$,

$\Rightarrow \Delta \theta = \dfrac{3}{2} \times 2\pi $

$\Rightarrow \Delta \theta = 3\pi $

So, $W = 600 \times 3\pi $

$\Rightarrow W = 1800\pi J$

$\Rightarrow W = 5654.86J$

**Therefore, the correct answer is option A.**

**Note:**Work done can also be calculated by work-energy theorem in a rotational motion. It says that work done during a rotational motion is equal to change in kinetic energy. In vector form the dot product of torque vector and radial vector is known as work done.

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