
A point moves in such a way that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane. Then find the locus of the point.
A. \[x - y + z = 2\]
B. \[x + y - z = 0\]
C. \[x - y + z = 0\]
D. \[x - y - z = 2\]
Answer
208.2k+ views
Hint: First, apply the distance formula and calculate the distance from any plane to that point. Then, substitute those values in the given condition. In the end, solve that equation and get the required answer.
Formula used: The distance formula:
The distance between the two points \[P\left( {{x_1},{y_1},{z_1}} \right)\] and \[Q\left( {{x_2},{y_2},{z_2}} \right)\] is: \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \]
Complete step by step solution: Given:
A point moves in a 3-D plane.
The sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane.
Let’s calculate the distance between that point and the \[xy\]-plane.
Let consider, the coordinates of the point are \[P\left( {x,y,z} \right)\].
We know that the coordinates of any point in xy-plane is \[Q\left( {x,y,0} \right)\].
Apply the distance formula \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \].
We get,
\[PQ = \sqrt {{{\left( {x - x} \right)}^2} + {{\left( {y - y} \right)}^2} + {{\left( {z - 0} \right)}^2}} \]
\[ \Rightarrow PQ = \sqrt {{z^2}} \]
\[ \Rightarrow PQ = \left| z \right|\]
Similarly, we get
The distance between that point and the \[yz\]-plane: \[\left| x \right|\]
The distance between that point and the \[xz\]-plane: \[\left| y \right|\]
It is given that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \xz\]-plane.
From the above information, we get
\[\left| z \right| + \left| x \right| = \left| y \right|\]
We know that the distance is always positive.
So,
\[x + z = y\]
\[ \Rightarrow x - y + z = 0\]
Thus, the locus of the point is \[x - y + z = 0\].
Thus, Option (C) is correct.
Note: A locus is a curve or shape that is formed by the collection of points whose position is represented by certain conditions.
Formula used: The distance formula:
The distance between the two points \[P\left( {{x_1},{y_1},{z_1}} \right)\] and \[Q\left( {{x_2},{y_2},{z_2}} \right)\] is: \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \]
Complete step by step solution: Given:
A point moves in a 3-D plane.
The sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane.
Let’s calculate the distance between that point and the \[xy\]-plane.
Let consider, the coordinates of the point are \[P\left( {x,y,z} \right)\].
We know that the coordinates of any point in xy-plane is \[Q\left( {x,y,0} \right)\].
Apply the distance formula \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \].
We get,
\[PQ = \sqrt {{{\left( {x - x} \right)}^2} + {{\left( {y - y} \right)}^2} + {{\left( {z - 0} \right)}^2}} \]
\[ \Rightarrow PQ = \sqrt {{z^2}} \]
\[ \Rightarrow PQ = \left| z \right|\]
Similarly, we get
The distance between that point and the \[yz\]-plane: \[\left| x \right|\]
The distance between that point and the \[xz\]-plane: \[\left| y \right|\]
It is given that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \xz\]-plane.
From the above information, we get
\[\left| z \right| + \left| x \right| = \left| y \right|\]
We know that the distance is always positive.
So,
\[x + z = y\]
\[ \Rightarrow x - y + z = 0\]
Thus, the locus of the point is \[x - y + z = 0\].
Thus, Option (C) is correct.
Note: A locus is a curve or shape that is formed by the collection of points whose position is represented by certain conditions.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Main 2022 (July 28th Shift 1) Physics Question Paper with Answer Key

JEE Main 2023 (January 29th Shift 2) Physics Question Paper with Answer Key

JEE Main 2022 (July 26th Shift 2) Maths Question Paper with Answer Key

JEE Main 2023 (January 25th Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Equation of Trajectory in Projectile Motion: Derivation & Proof

JEE Main Correction Window 2026- Edit Form Details, Dates and Link

Atomic Structure: Definition, Models, and Examples

Angle of Deviation in a Prism – Formula, Diagram & Applications

Hybridisation in Chemistry – Concept, Types & Applications

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Maths Chapter 9 Straight Lines

NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections

NCERT Solutions For Class 11 Maths Chapter 8 Sequences And Series

Collision: Meaning, Types & Examples in Physics

How to Convert a Galvanometer into an Ammeter or Voltmeter

