A point moves in such a way that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane. Then find the locus of the point.
A. \[x - y + z = 2\]
B. \[x + y - z = 0\]
C. \[x - y + z = 0\]
D. \[x - y - z = 2\]
Answer
269.4k+ views
Hint: First, apply the distance formula and calculate the distance from any plane to that point. Then, substitute those values in the given condition. In the end, solve that equation and get the required answer.
Formula used: The distance formula:
The distance between the two points \[P\left( {{x_1},{y_1},{z_1}} \right)\] and \[Q\left( {{x_2},{y_2},{z_2}} \right)\] is: \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \]
Complete step by step solution: Given:
A point moves in a 3-D plane.
The sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane.
Let’s calculate the distance between that point and the \[xy\]-plane.
Let consider, the coordinates of the point are \[P\left( {x,y,z} \right)\].
We know that the coordinates of any point in xy-plane is \[Q\left( {x,y,0} \right)\].
Apply the distance formula \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \].
We get,
\[PQ = \sqrt {{{\left( {x - x} \right)}^2} + {{\left( {y - y} \right)}^2} + {{\left( {z - 0} \right)}^2}} \]
\[ \Rightarrow PQ = \sqrt {{z^2}} \]
\[ \Rightarrow PQ = \left| z \right|\]
Similarly, we get
The distance between that point and the \[yz\]-plane: \[\left| x \right|\]
The distance between that point and the \[xz\]-plane: \[\left| y \right|\]
It is given that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \xz\]-plane.
From the above information, we get
\[\left| z \right| + \left| x \right| = \left| y \right|\]
We know that the distance is always positive.
So,
\[x + z = y\]
\[ \Rightarrow x - y + z = 0\]
Thus, the locus of the point is \[x - y + z = 0\].
Thus, Option (C) is correct.
Note: A locus is a curve or shape that is formed by the collection of points whose position is represented by certain conditions.
Formula used: The distance formula:
The distance between the two points \[P\left( {{x_1},{y_1},{z_1}} \right)\] and \[Q\left( {{x_2},{y_2},{z_2}} \right)\] is: \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \]
Complete step by step solution: Given:
A point moves in a 3-D plane.
The sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \[xz\]-plane.
Let’s calculate the distance between that point and the \[xy\]-plane.
Let consider, the coordinates of the point are \[P\left( {x,y,z} \right)\].
We know that the coordinates of any point in xy-plane is \[Q\left( {x,y,0} \right)\].
Apply the distance formula \[PQ = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2} + {{\left( {{z_2} - {z_1}} \right)}^2}} \].
We get,
\[PQ = \sqrt {{{\left( {x - x} \right)}^2} + {{\left( {y - y} \right)}^2} + {{\left( {z - 0} \right)}^2}} \]
\[ \Rightarrow PQ = \sqrt {{z^2}} \]
\[ \Rightarrow PQ = \left| z \right|\]
Similarly, we get
The distance between that point and the \[yz\]-plane: \[\left| x \right|\]
The distance between that point and the \[xz\]-plane: \[\left| y \right|\]
It is given that the sum of its distance from \[xy\]-plane and \[yz\]-plane remains equal to its distance from \xz\]-plane.
From the above information, we get
\[\left| z \right| + \left| x \right| = \left| y \right|\]
We know that the distance is always positive.
So,
\[x + z = y\]
\[ \Rightarrow x - y + z = 0\]
Thus, the locus of the point is \[x - y + z = 0\].
Thus, Option (C) is correct.
Note: A locus is a curve or shape that is formed by the collection of points whose position is represented by certain conditions.
Recently Updated Pages
Geometry of Complex Numbers Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Marks vs Rank: Estimate IIT Rank from Your Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

How to Convert a Galvanometer into an Ammeter or Voltmeter

Electron Gain Enthalpy and Electron Affinity Explained

