Answer
64.8k+ views
Hint In a converging lens, all the rays that are parallel to the principal axis will converge to a fixed point on the principal axis. Such a lens is called a convex lens. Here, we have to find where we have to place the object to get a magnified image. We have to use a ray diagram to find the right answer.
Complete Step by step solution
In this case, the magnification of the image will happen when the object is placed between \[F\]and $2F$
![](https://www.vedantu.com/question-sets/43a806fc-8c77-4549-8a9a-7c0b6e74947f3792797597828696834.png)
The image will be formed on the opposite side of the lens and it will be located beyond $2F$ on the other side. The image will be inverted. The size of the image will be greater than that of the size of the object. This means that the image is magnified. Magnification is the ratio of the image size to the object size. For inverted images magnification will be negative and for real images, magnification will be positive.
Here the correct options are not listed among the given options.
Additional Information
The location of the image is where the light rays are converging. If we place a screen at that point we will get the projection of the image on the screen. When the object is placed on the focus $F$and on the center of curvature $C$the image will be of the same size as that object. So there will not be any magnification.
Note
Alternate answer:
The image will be magnified when the object is placed between the focus $F$and the optic centre $O$of the lens. The image will be formed on the same side as the object. The image will be erect and virtual. Therefore a converging lens is also used as a magnifying glass.
![](https://www.vedantu.com/question-sets/20161fd2-0eca-4572-a76a-19172845aac06476416214108666850.png)
Complete Step by step solution
In this case, the magnification of the image will happen when the object is placed between \[F\]and $2F$
![](https://www.vedantu.com/question-sets/43a806fc-8c77-4549-8a9a-7c0b6e74947f3792797597828696834.png)
The image will be formed on the opposite side of the lens and it will be located beyond $2F$ on the other side. The image will be inverted. The size of the image will be greater than that of the size of the object. This means that the image is magnified. Magnification is the ratio of the image size to the object size. For inverted images magnification will be negative and for real images, magnification will be positive.
Here the correct options are not listed among the given options.
Additional Information
The location of the image is where the light rays are converging. If we place a screen at that point we will get the projection of the image on the screen. When the object is placed on the focus $F$and on the center of curvature $C$the image will be of the same size as that object. So there will not be any magnification.
Note
Alternate answer:
The image will be magnified when the object is placed between the focus $F$and the optic centre $O$of the lens. The image will be formed on the same side as the object. The image will be erect and virtual. Therefore a converging lens is also used as a magnifying glass.
![](https://www.vedantu.com/question-sets/20161fd2-0eca-4572-a76a-19172845aac06476416214108666850.png)
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)