
How can a converging lens produce a magnified image?
(A) When the object is beyond $2F$
(B) When the object is at $C$
(C) When the object is at $F$
(D) When the object is behind the mirror
Answer
140.1k+ views
Hint In a converging lens, all the rays that are parallel to the principal axis will converge to a fixed point on the principal axis. Such a lens is called a convex lens. Here, we have to find where we have to place the object to get a magnified image. We have to use a ray diagram to find the right answer.
Complete Step by step solution
In this case, the magnification of the image will happen when the object is placed between \[F\]and $2F$

The image will be formed on the opposite side of the lens and it will be located beyond $2F$ on the other side. The image will be inverted. The size of the image will be greater than that of the size of the object. This means that the image is magnified. Magnification is the ratio of the image size to the object size. For inverted images magnification will be negative and for real images, magnification will be positive.
Here the correct options are not listed among the given options.
Additional Information
The location of the image is where the light rays are converging. If we place a screen at that point we will get the projection of the image on the screen. When the object is placed on the focus $F$and on the center of curvature $C$the image will be of the same size as that object. So there will not be any magnification.
Note
Alternate answer:
The image will be magnified when the object is placed between the focus $F$and the optic centre $O$of the lens. The image will be formed on the same side as the object. The image will be erect and virtual. Therefore a converging lens is also used as a magnifying glass.

Complete Step by step solution
In this case, the magnification of the image will happen when the object is placed between \[F\]and $2F$

The image will be formed on the opposite side of the lens and it will be located beyond $2F$ on the other side. The image will be inverted. The size of the image will be greater than that of the size of the object. This means that the image is magnified. Magnification is the ratio of the image size to the object size. For inverted images magnification will be negative and for real images, magnification will be positive.
Here the correct options are not listed among the given options.
Additional Information
The location of the image is where the light rays are converging. If we place a screen at that point we will get the projection of the image on the screen. When the object is placed on the focus $F$and on the center of curvature $C$the image will be of the same size as that object. So there will not be any magnification.
Note
Alternate answer:
The image will be magnified when the object is placed between the focus $F$and the optic centre $O$of the lens. The image will be formed on the same side as the object. The image will be erect and virtual. Therefore a converging lens is also used as a magnifying glass.

Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

A point charge + 20mu C is at a distance 6cm directly class 12 physics JEE_Main

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
